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Leya [2.2K]
3 years ago
13

Is -1/2 rational or irrational

Mathematics
2 answers:
Vladimir79 [104]3 years ago
5 0
-1/2 is rational, have a good day
Hunter-Best [27]3 years ago
5 0
-1/2 is rational because it can be expressed as a ratio of 2 integers.

-1 and 2 are both integers because they are either whole numbers or of the opposite value (negative).
You might be interested in
Find three consecutive odd integers such that three times the sum of the first and second is 3 more than 3 times the third
Rufina [12.5K]

Answer:

3, 5, 7

Step-by-step explanation:

1st number: (2k+1)

2nd number: (2k+3)

3rd number: (2k+5), k∈Z

3*[(2k+1) + (2k+3)] = 3 + 3*(2k+5)

3*(4k+4)=3+6k+15

12k+12=18+6k

6k=6

k=1

1st number: (2k+1) = 3

2nd number: (2k+3)=5

3rd number: (2k+5)=7

4 0
3 years ago
Write the inequality shown in this graph.
kykrilka [37]

Answer:

y > -1/2 x + 4

Step-by-step explanation:

Equation of a line : (y-y1)/(y2-y1) = (x-x1)/(x2-x1)

(y-4)/(2-4)= (x-0)/(4-0)

(y-4)/-2 = x/4

(-y+4)/2 = x/4

-y+4 = 1/2 x

-y = 1/2 x - 4

y = -1/2 x + 4

the solutions of the inequality are the points above this line, so

y > -1/2 x + 4

8 0
2 years ago
What is the gcf of 12 78 and 90
Anuta_ua [19.1K]
The greatest common factor of 12, 78, and 90 is 6.

Factors are the numbers, that when multiplied with another number, equal the product.

Factors of 12: 1, 2, 3, 4, 6, and 12.
Factors of 78: 1, 2, 3, 6, 13, 26, 39, and 78.
Factors of 90: 1, 2, 3, 5, 6, 9, 10, 15, 18, 20, 45, and 90.

The Greatest Common Factor is the highest factor shared among the products. Thus proving 6 is the GCF.

I hope this helps!
7 0
3 years ago
2x2 – 5x + 67 = 0<br> What would be your first step in completing the square for the equation above?
7nadin3 [17]

Answer:

The first step is to divide all the terms by the coefficient of x^{2} which is 2.

The solutions to the quadratic equation 2x^2\:-\:5x\:+\:67\:=\:0 are:

x=\frac{5}{4}+i\frac{\sqrt{511}}{4},\:x=\frac{5}{4}-i\frac{\sqrt{511}}{4}

Step-by-step explanation:

Considering the equation

2x^2\:-\:5x\:+\:67\:=\:0

The first step is to divide all the terms by the coefficient of x^{2} which is 2.

so

\frac{2x^2-5x}{2}=\frac{-67}{2}

x^2-\frac{5x}{2}=-\frac{67}{2}

Lets now solve the equation by completeing the remaining steps

Write equation in the form: x^2+2ax+a^2=\left(x+a\right)^2

Solving for a,

2ax=-\frac{5}{2}x

a=-\frac{5}{4}

\mathrm{Add\:}a^2=\left(-\frac{5}{4}\right)^2\mathrm{\:to\:both\:sides}

x^2-\frac{5x}{2}+\left(-\frac{5}{4}\right)^2=-\frac{67}{2}+\left(-\frac{5}{4}\right)^2

x^2-\frac{5x}{2}+\left(-\frac{5}{4}\right)^2=-\frac{511}{16}

Completing the square

\left(x-\frac{5}{4}\right)^2=-\frac{511}{16}

Since, you had required to know the first step in completing the square for the equation above, I hope you have got the point, but let me quickly solve the remaining solution.

For f^2\left(x\right)=a the solution are f\left(x\right)=\sqrt{a},\:-\sqrt{a}

Solving

x-\frac{5}{4}=\sqrt{-\frac{511}{16}}

x-\frac{5}{4}=\sqrt{-1}\sqrt{\frac{511}{16}}

x-\frac{5}{4}=i\sqrt{\frac{511}{16}}       ∵ Applying imaginary number rule \sqrt{-1}=i

x-\frac{5}{4}=i\frac{\sqrt{511}}{\sqrt{16}}

-\frac{5}{4}=i\frac{\sqrt{511}}{4}

x=\frac{5}{4}+i\frac{\sqrt{511}}{4}

Similarly, solving

x-\frac{5}{4}=-\sqrt{-\frac{511}{16}}

x-\frac{5}{4}=-i\frac{\sqrt{511}}{4}    ∵ Applying imaginary number rule  \sqrt{-1}=i

x=\frac{5}{4}-i\frac{\sqrt{511}}{4}

Therefore, the solutions to the quadratic equation are:

x=\frac{5}{4}+i\frac{\sqrt{511}}{4},\:x=\frac{5}{4}-i\frac{\sqrt{511}}{4}

4 0
2 years ago
Find the area of a regular decagon with an apothem of 5 meters and a side length of3.25 meter. Round to the nearest tenth
topjm [15]
We know that

<span>The regular decagon can be divided into 10 congruent triangles
</span>so
area regular decagon=10*[area of one triangle]

area triangle=b*h/2
where
b=3.25 m
h is the aphotem
h=5 m
area=3.25*5/2----> area=8.125 m²

area regular decagon=10*[8.125]----> 81.25 m²

Area=81.3 m²

the answer is
81.3 m²
6 0
2 years ago
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