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4 years ago

Is -1/2 rational or irrational

Mathematics

2 answers:

Vladimir79 [104]4 years ago

5 0

-1/2 is rational, have a good day

Hunter-Best [27]4 years ago

5 0

-1/2 is rational because it can be expressed as a ratio of 2 integers.

-1 and 2 are both integers because they are either whole numbers or of the opposite value (negative).

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For Thanksgiving Break Nykouth and her family is going to visit relatives in Nebraska. Her dad has found a hotel room at the Hil

taurus [48]

Answer:

109n + 35

Step-by-step explanation:

I'm not sure what you are asking because you have no question in there

8 0

3 years ago

The numbers on two consecutively numbered gym lockers have a sum of 141. What are the locker numbers?

Tamiku [17]

Divide 141 by 2, getting 70.5. Since 70.5 is halfway between two consecutive integers, 70 and 71, these are the locker numbers. (P.S. This method only works with odd numbers.) 70+71=141.

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3 years ago

4/16 divided by 7/12 (simplified)

Leya [2.2K]

Answer:

$\frac{3}{7}$

Step-by-step explanation:

$\frac{4}{16} *\frac{12}{7}\\\\\frac{4}{4} * \frac{3}{7} \\\\1*\frac{3}{7} = \frac{3}{7}$

HAPPY:) I explained it!!

8 0

3 years ago

In the system shown below, what are the coordinates of the solution that lies in quadrant IV?

katrin2010 [14]

Answer:

The coordinates of the solution that lies in quadrant IV are (2, -5)

Step-by-step explanation:

We have 2 equations, the first of an ellipse and the second of a circumference.

$2x^2+y^2=33\\x^2+y^2+2y=19$

To solve the system solve the second equation for x and then substitute in the first equation

$x^2+y^2+2y=19\\\\x^2 = 19 -y^2 -2y$

So Substituting in the first equation we have

$x^2 = 19 -y^2 -2y\\\\2(19 -y^2 -2y)+y^2=33\\\\38 -2y^2-4y +y^2 = 33\\\\-y^2-4y+5=0\\\\y^2 +4y-5 = 0$

Now we must factor the quadratic expression.

We look for two numbers that multiply as a result -5 and add them as result 4.

These numbers are -1 and 5.

Then the factors are

$y^2 +4y-5 = 0\\\\(y-1)(y+5) = 0$

Therefore the system solutions are:

$y = 1$ ; $y = -5$

In the 4th quadrant the values of x are positive and the values of y are negative.

So we take the negative value of y and substitute it into the system equation to find x

$y=-5\\\\2x^2+(-5)^2=33\\\\2x^2 = 33-25\\\\2x^2 = 8\\\\x^2 = 4$

$x = 2$ , and $x= -2$

In the 4th quadrant the values of x are positive

So we take the positive value of x

<em><u>the coordinates of the solution that lies in quadrant IV are (2, -5)</u></em>

6 0

3 years ago

Read 2 more answers

Determine algebraically whether the function is even, odd, or neither even nor odd.

ololo11 [35]

Answer:

odd

Step-by-step explanation:

Just so you know there are shortcuts for determining if a polynomial function is even or odd. You just to make sure you use that x=x^1 and if you have a constant, write it as constant*x^0 (since x^0=1)

THEN!

If all of your exponents are odd then the function is odd

If all of your exponents are even then the function is even

Now you have -4x^3+4x^1

3 and 1 are odd it is an odd function

This a short cut not the legit algebra way

let me show you that now:

For it to be even you have f(-x)=f(x)

For it be odd you have f(-x)=-f(x)

If you don't have either of those cases you say it is neither

So let's check

plug in -x -4(-x)^3+4(-x)=-4*-x^3+-4x=-4x^3+-4x

that's not the same so not even

with if we factor out -1 .... well if we do that we get -(4x^3+4x)=-f(x)

so it is odd.

6 0

4 years ago