A quarterback throws a football to a teammate. The football is 6.5ft above the ground when it leaves the quarterback's hand. His teammate catches it 3.5s later, at a height above the ground of 5 ft. Determine the value of v, rounded to the nearest whole number.
2 answers:
Answer:
v=5.42m/s
Step-by-Step Explanation:
We can use conservation of energy to solve this
mgh=1/2mv^2
2gh=v^2
v=sqrt(2gh)
v=sqrt[2*9.8m/s^2*(6.5-5)]
v=5.42m/s
Answer:
i used a google calculator
v=5.42m/s
Step-by-step explanation:
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