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yawa3891 [41]
3 years ago
13

Indicate whether the study is an observational study or a controlled experiment. A group of boys is randomly divided into two gr

oups. One group watches violent cartoons for one​ hour, and the other group watches cartoons without violence for one hour. The boys are then observed to see how many violent actions they take in the next two​ hours, and the two groups are compared.
Mathematics
1 answer:
MariettaO [177]3 years ago
6 0

Answer:

Controlled Experiment

Step-by-step explanation:

The controlled experiment involves the experiment in which all factors are considered as constants whereas one factor is not fixed and that one is independent variable whose effect is to be tested. In short,  in controlled experiment one group of data contains control group and one or more other groups are examined by considering all other factors constant except for one factor. The control group is the group that doesn't receive any treatment whereas treatment is applied to experimental group and then effect of treatment is measured through comparing both groups.  

Here group of boys is divided in to two groups

The group watched violent cartoon= Experimental group

The group watched  cartoons without violence= Control group

The researchers want to know whether the violent actions of boys are linked to violent cartoon  and for this purpose these boys are divided into experimental group and control group and after 1 hour of cartoons watching the researcher will observed boys for next two hours.

Hence the study is Controlled experiment.

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S=a1/1-r
valentinak56 [21]

Answer:

4

Step-by-step explanation:

This is an <em>infinite geometric series</em>. This has a sum of  \frac{a}{1-r}

Where

a is the first term, and

r is the common ratio (one term divided by the previous term)

Let's figure out the first 2 terms by plugging in n = 1 first and then n = 2 for the series.

<u />

<u>First term:</u>

3(\frac{1}{4})^{n-1}\\=3(\frac{1}{4})^{1-1}\\=3(\frac{1}{4})^0\\=3(1)\\=3

<u>Second term:</u>

3(\frac{1}{4})^{n-1}\\=3(\frac{1}{4})^{2-1}\\=3(\frac{1}{4})^1\\=3(\frac{1}{4})\\=\frac{3}{4}

<em>Let's see the common ratio:  \frac{\frac{3}{4}}{3}\\=\frac{3}{4}*\frac{1}{3}\\=\frac{1}{4}</em>

<em />

<em>Thus we have a = 3 and r = 1/4</em><em>. Plugging into the formula of the infinite sum, we get:</em>

<em>s=\frac{a}{1-4}=\frac{3}{1-\frac{1}{4}}=\frac{3}{\frac{3}{4}}=3*\frac{4}{3}=4</em>

<em />

<em>So, </em><em>the answer is 4</em>

4 0
3 years ago
The sum of three numbers is 3. if the second number is subtracted from the sum of the first and third numbers, the result is 9.
Margaret [11]
Let the three numbers be x, y, and z.

If the sum of the three numbers is 3, then x+y+z=3

If subtracting the second number from the sum of the first and third numbers gives 9, then x+z-y=9

If subtracting the third number from the sum of the first and second numbers gives -5, then x+y-z=-5

This forms the system of equations:
[1] x+y+z=3
[2] x-y+z=9
[3] x+y-z=-5

First, to find y, let's take do [1]-[2]:
x+y+z=3
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2y=-6
y=-3

Then, to find z, let's do [1]-[3]:
x+y+z=3
-x+-y+z=5
2z=8
z=4

Now that you have y and z, plug them into [1] to find x:
x+y+z=3
x-3+4=3
x=2

So the three numbers are 2,-3, and 4.


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