17.5% is greater than 1/6
2x + 8 > 10
You first move + 8 to the other side, so you subtract 8
(When you see addition, you perform subtraction)
2x + 8 - 8 > 10 - 8
+ 8 and - 8 cancels out
2x > 2
Now, to isolate x, you should divide both sides by 2
(When you see multiplication, you perform division)
>
2 and 2 cancels out and we are left with
x > 1
So your final answer will be x > 1
Answer:
E) is correct, 2/3
Step-by-step explanation:
The points that are 20 inches apart from P form a circle that contains Q. We can suppose that P is in the position (0,0) and Q in the position (20,0) (we can rotate and move the circle without making any effect on the probability).
A point in the circle at distance 20 of Q has the form (20 cos(Ф), 20 sen(Ф) ) for certain angle Ф between 0 and 2π. Since it is at distance 20 of Q, we have that (20-20cos(Φ))² + (0-20sen(Φ))² = 20²=400, thus
400 - 800 cos(Φ) + 400cos²(Φ) + 400sen²(Φ) = 800-800cos(Φ) = 400, so
400 = 800cos(Φ)
cos(Φ) = 1/2
By looking at a trigonimetric table, you can find that Φ is either π/3 or 2π-π/3 = 5π/3.
As a result, the angles that will give you a point R at distance from Q greater than 20 are between π/3 and 5π/3, hence , the points that are a distance greater than 20 form a chord of length 20*(5π/3-π/3) = 80π/3. Comparing this with the perimeter of the circle (20*2π = 40π), this gives us a probability of 80π/3 / 40π = 2/3 that the point R is closer to P than it is to Q.
Answer:
i dont get it sorry
Step-by-step explanation:
Answer:
Therefore, the correct options are;
-P(fatigue) = 0.44
= 0.533
--P(drug and fatigue) = 0.32
P(drug)·P(fatigue) = 0.264
Step-by-step explanation:
Here we have that for dependent events,
From the options, we have;
= 0.533
P(drug) = 0.6
P(drug and fatigue) = 0.32
Therefore
P(drug and fatigue) = P(drug)×
= 0.6 × 0.533 = 0.3198 ≈ 0.32 = P(drug and fatigue)
Therefore, the correct options are;
-P(fatigue) = 0.44
= 0.533
--P(drug and fatigue) = 0.32
P(drug)·P(fatigue) = 0.264
Since P(fatigue) = 0.44 ∴ P(drug) = 0.264/0.44 = 0.6.