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Brut [27]
3 years ago
10

What am I doing sumbody please help

Mathematics
1 answer:
djyliett [7]3 years ago
8 0

Answer:

um, i think its d

Step-by-step explanation:

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V²=u²+2as make u as the subject <br><br>​
yKpoI14uk [10]

Answer:

u as the subject of the given formula is, u = \sqrt{v^{2}-2as }

Step-by-step explanation:

Given;

v² = u²+2as

To make u the subject of the formula, the following steps are taken;

v² = u²+2as

v²  - 2as = u²

take the square - root of both sides of the equation;

\sqrt{u^{2} } = \sqrt{v^{2}-2as } \\\\u = \sqrt{v^{2}-2as }

Thus, u as the subject of the given formula is, u = \sqrt{v^{2}-2as }

5 0
3 years ago
Can someone please help me with this math question?
KATRIN_1 [288]
I think it would be (D. 88)

~Hope This Helped~
3 0
3 years ago
Can someone also help me with this please and thankss
VMariaS [17]

Answer: The measure of angle 3 is 50 degrees.

Step-by-step explanation:

We know that angle 2 is 130 degrees.

Angle 1 and angle 2 are verticle angles which means that they are across and equal to each other.

So angle 1 and angle 2 are 130 degrees.

Add up both angle 1 and angle 2, 130 + 130 = 260.

Now, all of these angles add up to be 360 degrees in total as they make a circle and there are 360 degrees in one.

Subtract 260 from 360, 360 - 260 = 100.

Since both angle 3 and angle 4 are also verticle angles we need to split the 100 degrees evenly, 100 ÷ 2 = 50.

So, angle 3 is 50 degrees.

8 0
3 years ago
Read 2 more answers
The function f(x) = 5One-fifth is reflected over the y-axis. Which equations represent the reflected function? Select two option
postnew [5]

Answer:

The equations that represent the reflected function are

f(x)=5(\frac{1}{5})^{-x}

f(x)=5(5)^{x}

Step-by-step explanation:

The correct question in the attached figure

we have the function

f(x)=5(\frac{1}{5})^{x}

we know that

A reflection across the y-axis interchanges positive x-values with negative x-values, swapping x and −x.

therefore

f(−x) = f(x).

The reflection of the given function across the y-axis will be equal to

(Remember interchanges positive x-values with negative  x-values)

f(x)=5(\frac{1}{5})^{-x}

An equivalent form will be

f(x)=5(\frac{1}{5})^{(-1)(x)}=5[(\frac{1}{5})^{-1})]^{x}=5(5)^{x}

therefore

The equations that represent the reflected function are

f(x)=5(\frac{1}{5})^{-x}

f(x)=5(5)^{x}

9 0
3 years ago
Read 2 more answers
F(x) = x2 + 3x<br> g(x) = 2x – 5<br><br> Find f (x) + g(x)
AVprozaik [17]

Answer:

Step-by-step explanation:

3 0
3 years ago
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