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Brut [27]
3 years ago
10

What am I doing sumbody please help

Mathematics
1 answer:
djyliett [7]3 years ago
8 0

Answer:

um, i think its d

Step-by-step explanation:

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A(n) __________ is a combination of more than one inequality
Hoochie [10]

Answer:

A compound inequality is a sentence with two inequality statements joined either by the word “or” or by the word “and.” “And” indicates that both statements of the compound sentence are true at the same time. It is the overlap or intersection of the solution sets for the individual statements.

Step-by-step explanation:

4 0
3 years ago
Y = f(x) = 2x<br><br><br> Answer as a decimal
skad [1K]

Answer:

insufficient data

Step-by-step explanation:

please give complete question

4 0
2 years ago
There is a proportional relationship between a volume measured in cups and the same volume measured in tablespoons.
Arisa [49]

Answer:

1 cup for every 16 tablespoons or 1:16

6 0
3 years ago
A liquid oral concentrate of morphine sulfate contains 2.4 g of morphine sulfate in a 120-mL bottle. Calculate the concentration
MrMuchimi

Answer:

20 mg/ml.

Step-by-step explanation:

We have been given that a liquid oral concentrate of morphine sulfate contains 2.4 g of morphine sulfate in a 120-mL bottle.

\text{Concentration of morphine sulfate on g/mL basis}=\frac{\text{2.4 g}}{\text{120 ml}}

To convert the concentration of morphine sulfate on a mg/mL basis, we need to convert 2.4 grams to milligrams.

1 gram equals 1000 milligrams.

\text{Concentration of morphine sulfate on mg/mL basis}=\frac{\text{2.4 g}}{\text{120 ml}}\times\frac{\text{1,000 mg}}{\text{1 g}}

\text{Concentration of morphine sulfate on mg/mL basis}=\frac{2.4\times\text{1,000 mg}}{\text{120 ml}}

\text{Concentration of morphine sulfate on mg/mL basis}=\frac{2400\text{ mg}}{\text{120 ml}}

\text{Concentration of morphine sulfate on mg/mL basis}=\frac{20\text{ mg}}{\text{ml}}

Therefore, the concentration of morphine sulfate would be 20 mg per ml.

5 0
3 years ago
Graph y equals 1/2 x - 3​
Elis [28]

Answer:

Resulting plot in the image attached

Step-by-step explanation:

Start by making a table of (x,y) pairs that satisfy this equation. Notice that two pairs would be enough, but it is always safer to obtain at least three to see them actually "aligned".

We are trying to find values for y when x= 0, 2, and 4 to make our calculations simple:

y=\frac{1}{2} x-3

When x = 0 then: y=\frac{1}{2} (0)-3=-3 So we plot the value (0,-3) on the x-y plane.

When x = 2 then: y=\frac{1}{2} (2)-3=1-3=-2 So we plot the value (2,-2) on the x-y plane.

When x = 0 then: y=\frac{1}{2} (4)-3=2-3=-1 So we plot the value (4,-1) on the x-y plane.

Please see the points and the resulting line in the image attached

5 0
3 years ago
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