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3 years ago

How do you solve 8(2m+1) ?

Mathematics

2 answers:

Stella [2.4K]3 years ago

7 0

Answer:

16m+8

Step-by-step explanation:

distribute the 8

so multiply 8 by 2m which is 16m then multiply 8 by 1 which is 8 put em together and u get final solution of 16m+8

tino4ka555 [31]3 years ago

6 0

Answer:

Step-by-step explanation:

8(2m+1)=0

First equate to zero

Then open bracket

16m+8=0 make m subject of formulae

16m=8

m=8/16

m=1/2

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Find the 11th term of the following geometric sequence. 1,5, 25, 125, ...

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Answer:

9,765,625

Step-by-step explanation:

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2 years ago

if sofia has 40,000 dresses and she needs to put them in 1,000 boxes equally, how many dresses will fit in each box

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Answer:

40 dresses will fit in each box

Step-by-step explanation:

40,000 ÷ 1,000 = 40

Hope this helps

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2 years ago

Read 2 more answers

How do I solve this problem

Rufina [12.5K]

X+5+2x-2+90=180. combine like terms and solve like a normal algebra problem to find x. if you need to find the answer for a certain angle, plug in the value you got for x into one of the angle equations

8 0

2 years ago

Determine if each fraction is a terminating decimal or a repeating decimal. Write each fraction in the correct box.

Alja [10]

-7/9 is repeating
42/50 is terminating
-1/125 is terminating
-77/600 is repeating
179/200 is terminating
5/11 is terminating

The way to figure this out is just by dividing the Numerator (top number) by the denomiter (bottom number)
Example 5÷11=.45454545 repeating

6 0

2 years ago

Suppose Upper F Superscript prime Baseline left-parenthesis x right-parenthesis equals 3 x Superscript 2 Baseline plus 7 and Upp

Sedaia [141]

It looks like you're given

F'(x) = 3x² + 7

and

F (0) = 5

and you're asked to find F(b) for the values of b in the list {0, 0.1, 0.2, 0.5, 2.0}.

The first is done for you, F (0) = 5.

For the remaining b, you can solve for F(x) exactly by using the fundamental theorem of calculus:

$F(x)=F(0)+\displaystyle\int_0^x F'(t)\,\mathrm dt$

$F(x)=5+\displaystyle\int_0^x(3t^2+7)\,\mathrm dt$

$F(x)=5+(t^3+7t)\bigg|_0^x$

$F(x)=5+x^3+7x$

Then F (0.1) = 5.701, F (0.2) = 6.408, F (0.5) = 8.625, and F (2.0) = 27.

On the other hand, if you're expected to approximate F at the given b, you can use the linear approximation to F(x) around x = 0, which is

F(x) ≈ L(x) = F (0) + F' (0) (x - 0) = 5 + 7x

Then F (0) = 5, F (0.1) ≈ 5.7, F (0.2) ≈ 6.4, F (0.5) ≈ 8.5, and F (2.0) ≈ 19. Notice how the error gets larger the further away b gets from 0.

A better numerical method would be Euler's method. Given F'(x), we iteratively use the linear approximation at successive points to get closer approximations to the actual values of F(x).

Let y(x) = F(x). Starting with x₀ = 0 and y₀ = F(x₀) = 5, we have

x₁ = x₀ + 0.1 = 0.1

y₁ = y₀ + F'(x₀) (x₁ - x₀) = 5 + 7 (0.1 - 0) → F (0.1) ≈ 5.7

x₂ = x₁ + 0.1 = 0.2

y₂ = y₁ + F'(x₁) (x₂ - x₁) = 5.7 + 7.03 (0.2 - 0.1) → F (0.2) ≈ 6.403

x₃ = x₂ + 0.3 = 0.5

y₃ = y₂ + F'(x₂) (x₃ - x₂) = 6.403 + 7.12 (0.5 - 0.2) → F (0.5) ≈ 8.539

x₄ = x₃ + 1.5 = 2.0

y₄ = y₃ + F'(x₃) (x₄ - x₃) = 8.539 + 7.75 (2.0 - 0.5) → F (2.0) ≈ 20.164

4 0

2 years ago