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Licemer1 [7]
3 years ago
10

2. The following formula relates three quantities: Force (F), mass (m), and acceleration (a).

Mathematics
2 answers:
castortr0y [4]3 years ago
5 0

Let

F--------> represent the force

m--------> represent the mass

a-------> represent the acceleration

we know that

The formula that relates three quantities: Force (F), mass (m), and acceleration (a) is equal to

F=ma

<u>Part a)</u> Solve this equation for a

F=ma

Divide both sides by the mass

a=\frac{F}{m}

therefore

<u>the answer part a) is equal to</u>

a=\frac{F}{m}

<u>Part b) </u>Let the force be 25 units and the mass be m = 10 units. What is the acceleration, a?

we know that

the formula of acceleration is equal to

a=\frac{F}{m}

in this problem

we have

F=25\\m=10

Substitute the values n the formula

a=\frac{25}{10}

a=2.5

therefore

<u>the answer part b( is equal to</u>

a=2.5

<u>Part c)</u> Let the force be F = 25 units and the acceleration be a = 5 units. What is the mass, m?

we know that

F=ma

Solve for m

Divide both sides by the acceleration

m=\frac{F}{a}

in this problem

we have

F=25\\a=5

Substitute the values n the formula

m=\frac{25}{5}

m=5

therefore

<u>the answer Part c) is </u>

m=5

Ierofanga [76]3 years ago
3 0
(A): Divide each side by m and you will get \frac{F}{m} = a

(B): (You didn't tell me the units of force, so I can't give you the answer)

(C): m = 
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Volumeprism=volumecube times number of cubes
vprism/vcube=number of cubes

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the length and width of a rectangle are consecutive even integers. the area of the rectangle is 80 square units. what are the le
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X(x + 2) = 120sq units 

<span>Set it equal to 0 </span>
<span>x^2 + 2x - 120 = 0 </span>

<span>factor </span>
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<span>For the shorter side: </span>
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<span>Now that you have x, solve for the longer side which we said was represented by </span>
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<span>Proof </span>
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<span>120 = 120 </span>
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3 years ago
A = 1011 + 337 + 337/2 +1011/10 + 337/5 + ... + 1/2021
egoroff_w [7]

The sum of the given series can be found by simplification of the number

of terms in the series.

  • A is approximately <u>2020.022</u>

Reasons:

The given sequence is presented as follows;

A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021

Therefore;

  • \displaystyle A = \mathbf{1011 + \frac{1011}{3} + \frac{1011}{6} + \frac{1011}{10} + \frac{1011}{15} + ...+\frac{1}{2021}}

The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;

  • \displaystyle a_{n+1} = \mathbf{\frac{n^2 + 3 \cdot n + 2}{2}}

Therefore, for the last term we have;

  • \displaystyle 2043231= \frac{n^2 + 3 \cdot n + 2}{2}

2 × 2043231 = n² + 3·n + 2

Which gives;

n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0

Which gives, the number of terms, n = 2020

\displaystyle \frac{A}{2}  = \mathbf{ 1011 \cdot  \left(\frac{1}{2} +\frac{1}{6} + \frac{1}{12}+...+\frac{1}{4086460}  \right)}

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2} +\frac{1}{2} -  \frac{1}{3} + \frac{1}{3}- \frac{1}{4} +...+\frac{1}{2021}-\frac{1}{2022}  \right)

Which gives;

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2022}  \right)

\displaystyle  A = 2 \times 1011 \cdot  \left(1 - \frac{1}{2022}  \right) = \frac{1032231}{511} \approx \mathbf{2020.022}

  • A ≈ <u>2020.022</u>

Learn more about the sum of a series here:

brainly.com/question/190295

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2 years ago
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