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2 years ago

Write the equation of the line perpendicular to y = -3/4x that passes through the point (3,-8)

Mathematics

1 answer:

arlik [135]2 years ago

4 0

Answer:

y = $\frac{4}{3}$ x - 12

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - $\frac{3}{4}$ x ← is in slope- intercept form

with slope m = - $\frac{3}{4}$ , c = 0

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{-\frac{3}{4} }$ = $\frac{4}{3}$ , then

y = $\frac{4}{3}$ x + c ← is the partial equation

To find c substitute (3, - 8) into the partial equation

- 8 = 4 + c ⇒ c = - 8 - 4 = - 12

y = $\frac{4}{3}$ x - 12 ← equation of perpendicular line

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The formula for the standard deviation is:

$SD =\sqrt{\frac{\sum{(x-\mu)^2}}{N} }$

This can be further calculated as:

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Error = |3.16 - 8|

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Learn more here: brainly.com/question/18562832

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