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EleoNora [17]
3 years ago
11

Write the equation of the line perpendicular to y = -3/4x that passes through the point (3,-8)

Mathematics
1 answer:
arlik [135]3 years ago
4 0

Answer:

y = \frac{4}{3} x - 12

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - \frac{3}{4} x ← is in slope- intercept form

with slope m = - \frac{3}{4} , c = 0

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{-\frac{3}{4} } = \frac{4}{3} , then

y = \frac{4}{3} x + c ← is the partial equation

To find c substitute (3, - 8) into the partial equation

- 8 = 4 + c ⇒ c = - 8 - 4 = - 12

y = \frac{4}{3} x - 12 ← equation of perpendicular line

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