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3 years ago

How many hours of jogging at 5.5 miles per hour would be needed to lose 5 pounds

Mathematics

1 answer:

Mashutka [201]3 years ago

5 0

1.1 hours of jogging is needed to lose 5 pounds because 5.5 divided by 5 equals 1.1

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Use the multiplier method to increase £258 by 43%<br>You must show your working.

raketka [301]

Hello there, to answer your question...

258, percentage increased by 43% (percent) of its value

I hope this information helps.

8 0

3 years ago

Helpppp pleaseeee I need it tonight

snow_tiger [21]

What you want to first is substitute the numbers in for the variables in the equation

Since b= -5 , we will plug it in for -b

-5 + c = -13x

Now plug in -8 for c

-5 + (-8) = -13x

Add the numbers on the left side, which gives you -13.

-13 = -13x

Lastly, divide both sides by -13x, which will give you 1.

So x = 1

4 0

3 years ago

Someone help with #1

Drupady [299]

My answer was wrong, please delete this

6 0

3 years ago

Read 2 more answers

What is the answer to:<br> 18 - 5z + 6z > 3 + 6

miv72 [106K]

18 - 5z + 6z > 3 + 6
18 + z > 9
-18 -18
z > -9

3 0

3 years ago

Find the values of the measures shown when each value in the data set increases by 25. Mean: 109 Median: 104 Mode: 96 Range: 45

Vikki [24]

Answer:

The new values are as follows:

Mean: 134

Median: 129

Mode: 121

Range=45

Standard Deviation=3.6

Step-by-step explanation:

When a k real number is added to all the elements of the dataset, the new measures of center (mean, median, and mode) are simply found by adding the value k to the previous values. Thus

$Mean_{new}=Mean_{old}+k$

Here $Mean_{old}$ is 109 and k is 25 thus

$Mean_{new}=Mean_{old}+k\\Mean_{new}=109+25\\Mean_{new}=134$

Similarly

$Median_{new}=Median_{old}+k$

Here $Median_{old}$ is 104 and k is 25 thus

$Median_{new}=Median_{old}+k\\Median_{new}=104+25\\Median_{new}=129$

Also

$Mode_{new}=Mode_{old}+k$

Here $Mode_{old}$ is 96 and k is 25 thus

$Mode_{new}=Mode_{old}+k\\Mode_{new}=96+25\\Mode_{new}=121$

When a k real number is added to all the elements of the dataset, the new measures of variation (range and standard deviation) remain the same thus.

$Range_{new}=Range_{old}\\Range_{new}=45$

Similarly

$Standard\ Deviation_{new}=Standard\ Deviation_{old}\\Standard\ Deviation_{new}=3.6$

So the new values of mean, median, mode, range, and standard deviation are 134, 129, 121, 45, and 3.6 respectively.

4 0

3 years ago