Attach a photo so we can see the problem
Hello :
<span>7x-2y=1 ...(1)
2y=x-1...(2)
</span><span>substitution 2y in (1) :
</span>7x-(x-1) = 1
7x-x+1 = 1
7x = 0
x=0
in (2) : 2y = 0-1
2y = -1 y= -1/2
the <span>system have one solution : (0 ;-1/2)</span>
Note the improper fraction. Change it into a mixed fraction
3/2 = 2/2 + 1/2
2/2 = 1
5 + 1 1/2
Simplify.
5 + 1 = 6
6 1/2 is your answer
hope this helps
Answer:
it should be 2/12 and 9/11
Step-by-step explanation:
Answer:
Lines RQ and SP are perpendicular to SR
Step-by-step explanation:
SR are parallel to PQ so that means that RQ and SP are perpendicular to SR
