For 2, 3, 10, 11, 12, "intercept form" works nicely. .. x/(x-intercept) +y/(y-intercept) = 1
2) x/4 +y/4 = 1 . . . . . an equation .. x + y = 4 . . . . . . . . the equation in standard form
3) x/-3 +y/1 = 1 . . . . an equation .. x -3y = -3 . . . . . . . the equation in standard form
10) x/4 +y/2 = 1 .. x +2y = 4 . . . . . . . in standard form
11) x/-3 +y/5 = 1 .. 5x -3y = -15 . . . . . in standard form
12) x/-10 +y/16 = 1 .. 8x -5y = -80 . . . . . in standard form
For the rest, the 2-point form of the equation of a line will work. For points (x1, y1) and (x2, y2), the line through them can be written as .. y = (y2 -y1)/(x2 -x1)*(x -x1) +y1
Step-by-step explanation: need to find a basis for the solutions to the equation Ax = 0. To do this ... 0 0 0 1 −3. ⎤. ⎦. From this we can read the general solution, x = ⎡. ⎢. ⎢. ⎢. ⎢. ⎣ ... two vectors are clearly not multiples of one another, they also give a basis. So a basis ... 4.4.14 The set B = {1 − t2,t − t2,2 − 2t + t2} is a basis for P2.