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Lady_Fox [76]
3 years ago
6

Jeff reads 5/7 of a book in 4 hours. At this rate, how much did he read in 1 hour? Please answer this correctly. Don't put a lin

k i will report you.

Mathematics
1 answer:
leonid [27]3 years ago
5 0

Answer:

Jeff read 5/28 of a book in 1 hour.

Step-by-step explanation:

The rate given is 5/7 of a book read in 4 hours.

If the questions asks how much he read in 1 hour, it means the answer needed is a unit rate.

A unit rate is a rate per unit. In this case, a rate per hour.

Let’s find how much Jeff read in 1 hour:

5/7 in 4 hours is the rate given so:

5/7 ÷ 4

= 5/7 x 1/4

= 5/28 (already simplified/final answer)

SO, Jeff read 5/28 of the book in 1 hour.

Brainliest? Hope this helped!

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Find the GCF from the two numbers and rewrite the sum using nthe distributive property
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Answer:

The greatest common factor is 6.

Step-by-step explanation:

Greatest common factor is 6. If you use the distributive property then the answer would be 6(4) + 6(6) or 6(4+6). Then you distribute the 6 to each digit and should get 24+36.

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3 years ago
There are four erasers but only three pencils write the ratio of erasers to pencils
iris [78.8K]
4:3
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When is a sum of a geometric sequence finit and when is it infinite?
Olin [163]
Hopefully this will help you

3 0
3 years ago
If you had 1052 toothpicks and were asked to group them in powers of 6, how many groups of each power of 6 would you have? Put t
sukhopar [10]

1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

The number 1052, written as a base 6 number is 4512

Given: 1052 toothpicks

To do: The objective is to group the toothpicks in powers of 6 and to write the number 1052 as a base 6 number

First we note that, 6^{0}=1,6^{1}=6,6^{2}=36,6^{3}=216,6^{4}=1296

This implies that 6^{4} exceeds 1052 and thus the highest power of 6 that the toothpicks can be grouped into is 3.

Now, 6^{3}=216 and 216\times 5=1080, 216\times 4=864. This implies that 216\times 5 exceeds 1052 and thus there can be at most 4 groups of 6^{3}.

Then,

1052-4\times6^{3}

1052-4\times216

1052-864

188

So, after grouping the toothpicks into 4 groups of third power of 6, there are 188 toothpicks remaining.

Now, 6^{2}=36 and 36\times 5=180, 36\times 6=216. This implies that 36\times 6 exceeds 188 and thus there can be at most 5 groups of 6^{2}.

Then,

188-5\times6^{2}

188-5\times36

188-180

8

So, after grouping the remaining toothpicks into 5 groups of second power of 6, there are 8 toothpicks remaining.

Now, 6^{1}=6 and 6\times 1=6, 6\times 2=12. This implies that 6\times 2 exceeds 8 and thus there can be at most 1 group of 6^{1}.

Then,

8-1\times6^{1}

8-1\times6

8-6

2

So, after grouping the remaining toothpicks into 1 group of first power of 6, there are 2 toothpicks remaining.

Now, 6^{0}=1 and 1\times 2=2. This implies that the remaining toothpicks can be exactly grouped into 2 groups of zeroth power of 6.

This concludes the grouping.

Thus, it was obtained that 1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

Then,

1052=4\times6^{3}+5\times6^{2}+1\times6^{1}+2\times6^{0}

So, the number 1052, written as a base 6 number is 4512.

Learn more about change of base of numbers here:

brainly.com/question/14291917

6 0
2 years ago
Hello please help i’ll give brainliest
HACTEHA [7]

Answer:

b. option Is the correct answer right

3 0
3 years ago
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