The formula for aerobic respiration in animals can be shown by the equation below. A glucose molecule is broken down by enzymes in the presence of oxygen to make carbon dioxide, water, and ATPs. Carbon IV oxide is expelled by the lungs.
C₆H₁₂O₆ + 6O₂ --> 6CO₂ + 6H₂O + 38 ATP
This process occurs in two stages. Glycolysis (that does not require oxygen) occurs in the cytoplasm of cells. The products of the glucose breakdown in this stage is pyruvate, CO₂ and 2 net ATPs. The pyruvate is then converted to acetyl-CoA that enters the second stage called Citric/Krebs cycle. This second stage happens in the mitochondria. The products are CO₂, H₂O and 34 ATPs
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The correct answer is D. Homeostasis and transport of molecules
Explanation:
The diagram presented shows the movement of glucose from outside the cell to inside it. Also, this diagram illustrates this process occurs through the cell membrane and there is a higher concentration outside the cell.
This complex process illustrates the transport of molecules in the cell, which refers to a mechanism that allows molecules and substances to move in and out of a cell. Moreover, this process implies molecules (in this case glucose) move to one area with a lower concentration to preserve equilibrium as shown by the diagram. Additionally, this equilibrium is part of homeostasis which is a set of mechanisms to main an equilibrium in the cell, including appropriate levels of glucose and other substances.
<h3>
Transitional fossils</h3>
Transitional fossils are any fossilized remains of a life form which show common traits to both an ancestral group and its derived descendant group.
<em> Australopithecus afarensis </em>is a hominid that represents an evolutionary transition between modern bipedal humans and their quadrupedal ape ancestors.
Similarities in DNA
All species in the world share some amount of DNA. Species that are more related to each other share bigger amount of DNA than species that are less related. For example fruit fly and modern humans share 61% of their genome and chimps and humans share 96%.
Evolution of the eye
The PAX6 gene controls where eyes develop in animals ranging from fruit flies, octopuses, to mice and humans.
Because it makes it easier for the air to flow through our bodies.
Answer:
Option D is correct.
Explanation:
Option a) given in the option that if promoter is altered it will inhibit transcription which is the process by which information present in DNA converted to mRNA which require RNA polymerase which bind to promoter site so if promoter is altered RNA polymerase will not bind so transcription will be inhibited but above question is asking about inhibition of translation due to binding of miRNA-delta molecule to Q mRNA so this option can be eliminated.
Option b if miRNA binding site sequence is altered miRNA molecule will not be able to bind to Q mRNA so translation will not be inhibited hence option b is incorrect
Option c translation of Q mRNA is inhibited when miRNA - delta is present not absent
So option c can be eliminated
Option d if miRNA binding sequence is altered miRNA molecule if present will not bind to Q mRNA hence translation of Q mRNA will occur & not inhibited
Hence option d is correct
