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USPshnik [31]
3 years ago
14

Mr.Vegas team raised $6573 selling snacks at an archery meet.This ammount will pay registration fee for 48 students to attend an

archery workshop. There will be $45 left to start a savings account for Next year's workshop. How much does it cost for one student to attend the archery workshop?
Mathematics
1 answer:
nika2105 [10]3 years ago
3 0

Answer: $136

Step-by-step explanation:

$6573 - $45

= $6528

$6528 divided by 48

= $136

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Solve the system of linear equations by substitution.<br><br> y−x=0<br> 2x−5y=9
Otrada [13]

Answer:

x = -3

y = -3

in point form is ( -3, -3 )

Step-by-step explanation:


4 0
3 years ago
Slope of the line that passes through (6,0) and (0,-6)
lisov135 [29]

Hey there!

The formula is:

• m = rise / run

• m = y₂ – y₁ / x₂ – x₁

• y₂ = –6

• y₁ = 0

• x₂ = 0

• x₁ = 6

• Equation: “–6 – 0 / 0 – 6”

–6 – 0 = –6 ⬅️ numerator (TOP number)

0 – 6 = –6 ⬅️ denominator (BOTTOM number)

Equation: –6 / –6

SOLVE above and you will have your ANSWER.

–6 / –6 = 1 because double negatives makes a negative.

The slope of line that passes through your given points is: 1

Answer: 1 ☑️

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

4 0
3 years ago
Helen is putting a fence around her flower garden, which is in the shape of half of a circle and a rectangle. If the semicircle
erastova [34]

Answer:

Part 1) Helen will need 38 feet of fencing

Part 2) The perimeter around the three sides of the rectangular section of the garden is 27 feet

Part 3) The approximate distance around half of the circle is 11 feet

Step-by-step explanation:

Part 1) How much fencing will Helen need?

Find out the perimeter

we know that

The perimeter of the figure is equal to the sum of three sides of the rectangular section plus the circumference of a semicircle

so

P=2L+W+\frac{1}{2}\pi D

we have

L=10\ ft\\W=7\ ft\\D=7\ ft\\\pi =\frac{22}{7}

substitute

P=2(10)+7+\frac{1}{2}(\frac{22}{7})(7)

P=20)+7+11=38\ ft

therefore

Helen will need 38 feet of fencing

Part 2)  What is the perimeter around the three sides of the rectangular section of the garden?

P=2L+W

we have

L=10\ ft\\W=7\ ft

substitute

P=2(10)+7

P=20+7=27\ ft

therefore

The perimeter around the three sides of the rectangular section of the garden is 27 feet

Part 3) What is the approximate distance around half of the circle?

Find the circumference of semicircle

C=\frac{1}{2}\pi D

we have

D=7\ ft\\\pi =\frac{22}{7}

substitute

C=\frac{1}{2}(\frac{22}{7})(7)

C=11\ ft

therefore

The approximate distance around half of the circle is 11 feet

4 0
2 years ago
Read 2 more answers
Solve the equation-4(x+10)-6=-3(x-2)<br>​
marta [7]

Answer:

x = -52

Step-by-step explanation:

-4x-46+46=-3x+6+46

-4x=-3x+52

-4x+3x=-3x+52+3x

8 0
2 years ago
Read 2 more answers
Please help I need help
qaws [65]

The first answer of part A is 32

So 4y means you have to multiply 4 by y, which is 20 since 4x5=20

And then you add 12, which is 32.

The second answer to part A is 40

With the second question of part a, the expression is basically saying 4 times whatever 5+3 is. So 5+3= 8, and 4(8) is 40

For part B, they are equivalent because let’s pretend y=2. 12+4y= 20. And then 4(y+3) would equal 20 because 4(2)=8 and 4(3)=12 and 8+12=20. This might not be the answer that your teacher is looking for, but it’s still a right answer so technically they can’t say it’s wrong unless you have a super unfair teacher

3 0
3 years ago
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