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vekshin1
3 years ago
14

Select the pairs of ratios that form a true proportion. Choose all that apply A 3: 6 and 5:10 B 4/12 and 6/18 C 20/5 and 10/3 D

24: 36 and 8: 9
Mathematics
1 answer:
Naddika [18.5K]3 years ago
5 0

Answer:

The only grouping that is a true proportion is B.

Step-by-step explanation:

To tell if two are proportional, simply multiply the numerator from the first by the denominator of the second. Then multiply the denominator from the first and the numerator for the second. If the two products are the same, then it is proportional.

B) 4/12 = 6/18

4*18 = 12 * 6

72 = 72

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Paraphin [41]

The correct answer is 3x+90=180

<em>Because you add the 2x and the x and you get 3x then there is a 90 degree angles so you add that and =180</em>

<em>Once you put it in the equation you can subtract 90 from 180 and you get 90 which you then divided by 3x and x equals 30</em>

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4 0
3 years ago
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3 years ago
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Tresset [83]

9x^2 -c =d

add c to each side

9x^2 = c+d

divide by 9

x^2=(c+d)/9

take the square root on each side

x = +- sqrt ((c+d)/9)

simplify

x = +- 1/3 sqrt (c+d)

Answer: 1/3 sqrt (c+d), - 1/3 sqrt (c+d)

7 0
3 years ago
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Which side lengths form a right triangle?
lilavasa [31]

Answer:

About anything that adds up to 90...

Step-by-step explanation:

3 0
2 years ago
There are 412 students and 20 teachers taking buses on a trip to a museum. Each bus can seat a maximum of 48. Which inequality g
-BARSIC- [3]

The inequality \mathrm{b} \geq \frac{\text { total number of travelers }}{\text { capacity of each bus }} gives the least number of buses, b, needed for the trip. The least number of buses is 9

<u>Solution:</u>

Given that, There are 412 students and 20 teachers taking buses on a trip to a museum.  

Each bus can seat a maximum of 48.  

We have to find which inequality gives the least number of buses, b, needed for the trip?

Now, there are 412 students and 20 teachers, so in total there are 412 + 20 = 432 travelers

<em><u>The number of buses required “b” is given as:</u></em>

\text { (b) } \geq \frac{\text { total number of travelers }}{\text { capacity of each bus }}

\text { So, number of buses required } \geq \frac{432}{48}

Number of buses required ≥  9 buses.

But least number will be 9 from the above inequality.

Hence, the inequality \mathrm{b} \geq \frac{\text {total number of travelers}}{\text {capacity of each bus}} gives least count of busses and least count is 9.

6 0
3 years ago
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