3 years ago

Evaluate the expression below for x = 2, y = -3, and z = -1.

Mathematics

1 answer:

Mariana [72]3 years ago

4 0

B -5
The answer is -5

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Need some help :

kondor19780726 [428]

Answer:

Step-by-step explanation:

3 0

3 years ago

*WILL GIVE BRAINLIEST IF U GIVE BEST ANSWER AND HELP ME PASS THIS*<br> Solve for g.<br> 2 = g4− 1

KonstantinChe [14]

Answer:

0.75 is it the answer

Step-by-step explanation:

6 0

2 years ago

Multiply or divide as indicated. Y^-9•y^-8•y^10

BabaBlast [244]

Answer:

1 / y^7

Step-by-step explanation:

Y^-9•y^-8•y^10

= y^10 / y^9•y^8

= y^10 / y^17

= 1 / y^7

8 0

3 years ago

Which measurement is equal to 6 kilograms?

lidiya [134]

Answer:

6000 metres is equal to 6 kilograms

5 0

3 years ago

If A and B are independent events with P(A) = .5 and P(B) = .2, find the following:a) P(A U B)b) P(A^c ? B^c)c) P(A^c U B^c)**No

Effectus [21]

If A and B are independent, then $P(A\cap B)=P(A)P(B)$ .

$P(A\cup B)=P(A)+P(B)-P(A\cap B)=P(A)+P(B)-P(A)P(B)$

$P(A\cup B)=0.5+0.2-0.5\cdot0.2$

$\boxed{P(A\cup B)=0.6}$

b. I'm guessing the ? is supposed to stand for intersection. We can use DeMorgan's law for complements here:

$P(A^c\cap B^c)=P(A\cup B)^c=1-P(A\cup B)$

$P(A^c\cap B^c)=1-0.6$

$\boxed{P(A^c\cap B^c)=0.4}$

c. DeMorgan's law can be used here too:

$P(A^c\cup B^c)=P(A\cap B)^c=1-P(A\cap B)=1-P(A)P(B)$

$P(A^c\cup B^c)=1-0.5\cdot0.2$

$\boxed{P(A^c\cup B^c)=0.9}$

4 0

2 years ago