Ask question

Ask question

All categories

Dmitry_Shevchenko [17]

3 years ago

14

Mrs Jenkins picked some tomatoes from her garden. She used 5/9 of the tomatoes to make pasta sauce. Then she used 3/4 of the rem

ainder to make a salad. What fraction of the tomatoes did mrs Jenkins use to make the salad?

1 answer:

dedylja [7]3 years ago

3 0

Answer:

Final answer is 1/3.

Step-by-step explanation:

Question says that Mrs Jenkins picked some tomatoes from her garden. She used 5/9 of the tomatoes to make pasta sauce. After that she used 3/4 of the remainder to make a salad. Now we need to find about what fraction of the tomatoes did Mrs Jenkins use to make the salad.

As she used 5/9 of the tomatoes to make pasta sauce.

Now remaining amount of tomatoes = 1- 5/9 = 9/9 -5/9 = 4/9

Then she used 3/4 of the remainder to make a salad. So fraction of the tomatoes did Mrs Jenkins use to make the salad = (4/9)(3/4)=12/36=1/3

Hence final answer is 1/3.

You might be interested in

What is the volume of the composite object below?

castortr0y [4]

Answer:

216 cubic inches

Step-by-step explanation:

(9)(3)(3)=81

(3)(3)(9)=81

(3)(3)(6)=54

81+81+54=216

So, it's 216 cubic inches in volume.

6 0

3 years ago

if I went to store with 90.00 and spent 36.81 and got 20% off what would I have left need answer fast thanks

vichka [17]

I'm guessing the 20 percent off is from the $36.81 so you take 36.81 times 0.80 making it $29.448. Take 90 dollars and minus that amount.

Answer: $60.552
Rounded Answer: $60.55 or $60.60 or $61

Not sure if this helped, but yeah.....

3 0

3 years ago

Answer fast!!!!!!!!!!!!!!!!!!!!!!!!!!

Veronika [31]

Answer:

Choice b.

Step-by-step explanation:

170 is a little more than half of 330 so that's the onee.

7 0

3 years ago

Solution for dy/dx+xsin 2 y=x^3 cos^2y

vichka [17]

Rearrange the ODE as

$\dfrac{\mathrm dy}{\mathrm dx}+x\sin2y=x^3\cos^2y$
$\sec^2y\dfrac{\mathrm dy}{\mathrm dx}+x\sin2y\sec^2y=x^3$

Take $u=\tan y$ , so that $\dfrac{\mathrm du}{\mathrm dx}=\sec^2y\dfrac{\mathrm dy}{\mathrm dx}$ .

Supposing that $|y|$ , we have $\tan^{-1}u=y$ , from which it follows that

$\sin2y=2\sin y\cos y=2\dfrac u{\sqrt{u^2+1}}\dfrac1{\sqrt{u^2+1}}=\dfrac{2u}{u^2+1}$
$\sec^2y=1+\tan^2y=1+u^2$

So we can write the ODE as

$\dfrac{\mathrm du}{\mathrm dx}+2xu=x^3$

which is linear in $u$ . Multiplying both sides by $e^{x^2}$ , we have

$e^{x^2}\dfrac{\mathrm du}{\mathrm dx}+2xe^{x^2}u=x^3e^{x^2}$
$\dfrac{\mathrm d}{\mathrm dx}\bigg[e^{x^2}u\bigg]=x^3e^{x^2}$

Integrate both sides with respect to $x$ :

$\displaystyle\int\frac{\mathrm d}{\mathrm dx}\bigg[e^{x^2}u\bigg]\,\mathrm dx=\int x^3e^{x^2}\,\mathrm dx$
$e^{x^2}u=\displaystyle\int x^3e^{x^2}\,\mathrm dx$

Substitute $t=x^2$ , so that $\mathrm dt=2x\,\mathrm dx$ . Then

$\displaystyle\int x^3e^{x^2}\,\mathrm dx=\frac12\int 2xx^2e^{x^2}\,\mathrm dx=\frac12\int te^t\,\mathrm dt$

Integrate the right hand side by parts using

$f=t\implies\mathrm df=\mathrm dt$
$\mathrm dg=e^t\,\mathrm dt\implies g=e^t$
$\displaystyle\frac12\int te^t\,\mathrm dt=\frac12\left(te^t-\int e^t\,\mathrm dt\right)$

You should end up with

$e^{x^2}u=\dfrac12e^{x^2}(x^2-1)+C$
$u=\dfrac{x^2-1}2+Ce^{-x^2}$
$\tan y=\dfrac{x^2-1}2+Ce^{-x^2}$

and provided that we restrict $|y|$ , we can write

$y=\tan^{-1}\left(\dfrac{x^2-1}2+Ce^{-x^2}\right)$

5 0

3 years ago

One of Tyler’s chores is to feed the chickens. Two bags of chicken feed will last 5 days. How many days will 8 bags of chicken f

aleksley [76]

Answer:

20days

Step-by-step explanation:

1 bag feed : 5/2 = 2.5 days

8 bags feed : 2.5*8 = 20 days

5 0

3 years ago