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34kurt
3 years ago
9

Help please i need help

Mathematics
2 answers:
pochemuha3 years ago
6 0
I think these hopefully should be correct

A- 8
B- 41
C-40
Kruka [31]3 years ago
5 0

Answer:

A=6

B=41

c=42

Step-by-step explanation:

You might be interested in
John runs a computer software store. Yesterday he counted 123 people who walked by the store, 56 of whom came into the store. Of
vaieri [72.5K]

Answer:

a) There is a 45.53% probability that a person who walks by the store will enter the store.

b) There is a 41.07% probability that a person who walks into the store will buy something.

c) There is a 18.70% probability that a person who walks by the store will come in and buy something.

d) There is a 58.93% probability that a person who comes into the store will buy nothing.

Step-by-step explanation:

This a probability problem.

The probability formula is given by:

P = \frac{D}{T}

In which P is the probability, D is the number of desired outcomes and T is the number of total outcomes.

The problem states that:

123 people walked by the store.

56 people came into the store.

23 bought something in the store.

(a) Estimate the probability that a person who walks by the store will enter the store.

123 people walked by the store and 56 entered the store, so T = 123, D = 56.

So

P = \frac{D}{T} = \frac{56}{123} = 0.4553

There is a 45.53% probability that a person who walks by the store will enter the store.

(b) Estimate the probability that a person who walks into the store will buy something.

56 people came into the store and 23 bought something, so T = 56, D = 23.

So

P = \frac{D}{T} = \frac{23}{56} = 0.4107

There is a 41.07% probability that a person who walks into the store will buy something.

(c) Estimate the probability that a person who walks by the store will come in and buy something.

123 people walked by the store and 23 came in and bought something, so T = 123, D = 23.

So

P = \frac{D}{T} = \frac{23}{123} = 0.1870

There is a 18.70% probability that a person who walks by the store will come in and buy something.

(d) Estimate the probability that a person who comes into the store will buy nothing.

Of the 56 people whom came into the store, 23 bought something. This means that 56-23 = 33 of them did not buy anything. So:

D = 33, T = 56

P = \frac{D}{T} = \frac{33}{56} = 0.5893

There is a 58.93% probability that a person who comes into the store will buy nothing.

8 0
3 years ago
KX
frozen [14]

5x-3x=5-1

2x=2

x=1

Step-by-step explanation:

make the xes one side and the numb one side first and solve:

3 0
1 year ago
Read 2 more answers
Select the correct answer from each drop-down menu
Yakvenalex [24]

Answer:

First row. = -393 74 287

Second row = 471. 162 91

Third row =251 222 - 349

Step-by-step explanation:

For the first row

Cofactor of 12= (-8*15)-(21*13)

= -120-273

= -393

Cofactor of 23 = (11*15)-(7*13)

= 165-91

= 74

Cofactor of -6 = (11*21)-(-7*8)

= 231+56

= 287

For the second row

Cofactor of 11 = (23*15)-(21*-6)

= 345+126

= 471

Cofactor of -8 = (12*15)-(7*-6)

= 120 + 42

= 162

Cofactor of 13 (12*21)-(23*7)

= 252-161

= 91

For third row

Cofactor of 7= (23*13)-(-8*-6)

= 299-48

= 251

Cofactor of 21 = (12*13)-(11*-6)

= 156+66

=222

Cofactor of 15 = (12*-8)-(11*23)

= -96 - 253

=- 349

8 0
3 years ago
How do I go about solving (27x^3/8y^9)^5/3? And what is the role of the numerator and denominator?
MrRissso [65]
\left( \frac{27x^3}{8y^9}\right)^ \frac{5}{3}  \\\\\\ =\left( \frac{(3x)^3}{(2y^3)^3}\right)^ \frac{5}{3} \\\\\\ =  \frac{(3x)^{3 \times  \frac{5}{3} }}{(2y^3)^{3 \times  \frac{5}{3} }} \\\\\\ =\frac{(3x)^5}{(2y^3)^{5 }} \\\\\\ =\frac{243x^5}{32y^{15}}

Now, If the exponent was negative like you asked....

\left( \frac{27x^3}{8y^9}\right)^ {-\frac{5}{3}} \\\\\\ =\left( \frac{8y^9}{27x^3}\right)^ {\frac{5}{3}}\\\\\\ =\left( \frac{(2y^3)^3}{(3x)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(2y^3)^{3 \times \frac{5}{3} }}{(3x)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(2y^3)^{5 }}{(3x)^5} \\\\\\ =\frac{32y^{15}}{243x^5}

5 0
3 years ago
The three volumes of Lord of the Rings sit in order on a shelf. Each is 1 1/4 inches thick, comprising an inch of pages and 1/8
zubka84 [21]

Answer:

3 1/2

Step-by-step explanation:

Just trust me

8 0
3 years ago
Read 2 more answers
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