Explain how to model the division of -20 by -5 on a number line.

Ben deposited $6,500 in a simple interest account that pays 2.8% interest annually. If Ben leaves the money in the account for 1

Paladinen [302]

Answer: $2184

Step-by-step explanation:

(6800)(0.028)(12) = 2184

3 0

3 years ago

Please answer quickly, more might be coming soon. 50 Points!

Brut [27]

Answer:

2) ∠SDH and ∠SDT are right angles because SD ⊥ HT.

3) $\bar{SH}\cong \bar{ST}$ as it is given in the question.

4) $\bar{SD}\cong \bar{SD}$ is the reflexive property.

5) ΔSHD ≅ ΔSTD by RHS congruency.

Step-by-step explanation:

Given in the question:

$\bar{SH}\cong \bar{ST}\\\bar{SD}\perp \bar{HT}$

In ΔSHD and ΔSTD

$\bar{SH}\cong \bar{ST}$ (Given)

$\angle SDH\cong \angle SDT=90^o$ (SD ⊥ HT)

$\bar{SD}\cong \bar{SD}$ (Common)

Therefore, $\Delta SHD\cong \Delta STD$ (By RHS rule)

Reflexive property of congruency is defined as the property in which something is equal to itself. Hence, the reflexive property of these two triangles is $\bar{SD}\cong \bar{SD}$

5 0

3 years ago

!I WILL GIVE YOU 50 POINTS!!!!!!!!!!!! (if it's worng you will be reported)

vesna_86 [32]

The answer is x=5+10y

6 0

3 years ago

Solve for x.4(2x + 3) = 3x + 3 + 2x

ElenaW [278]

Answer:

The value of x is -3.

Explanation:

Given the equation:

$4\mleft(2x+3\mright)=3x+3+2x$

Step 1: Distribute 4 in the left-hand side.

$\begin{gathered} 4\mleft(2x)+4(3\mright)=3x+3+2x \\ 8x+12=3x+2x+3 \\ 8x+12=5x+3 \end{gathered}$

Step 2: Collect like terms.

$\begin{gathered} 8x-5x=3-12 \\ 3x=-9 \end{gathered}$

Step 3: Divide both sides by 3.

$\begin{gathered} \frac{3x}{3}=-\frac{9}{3} \\ x=-3 \end{gathered}$

The value of x is -3.

3 0

1 year ago

The time it takes for a planet to complete its orbit around a particular star is called the? planet's sidereal year. The siderea

BartSMP [9]

Answer:

(a) See below

(b) r = 0.9879

(c) y = -12.629 + 0.0654x

(d) See below

(e) No.

Step-by-step explanation:

(a) Plot the data

I used Excel to plot your data and got the graph in Fig 1 below.

(b) Correlation coefficient

One formula for the correlation coefficient is

$r = \dfrac{\sum{xy} - \sum{x} \sum{y}}{\sqrt{\left [n\sum{x}^{2}-\left (\sum{x}\right )^{2}\right]\left [n\sum{y}^{2} -\left (\sum{y}\right )^{2}\right]}}$

The calculation is not difficult, but it is tedious.

(i) Calculate the intermediate numbers

We can display them in a table.

x y xy x² y²

36 0.22 7.92 1296 0.05

67 0.62 42.21 4489 0.40

93 1.00 93.00 20164 3.46

433 11.8 5699.4 233289 139.24

887 29.3 25989.1 786769 858.49

1785 82.0 146370 3186225 6724

2797 163.0 455911 7823209 26569

3675 248.0 911400 13505625 61504

9965 537.81 1545776.75 25569715 95799.63

(ii) Calculate the correlation coefficient

$r = \dfrac{\sum{xy} - \sum{x} \sum{y}}{\sqrt{\left [n\sum{x}^{2}-\left (\sum{x}\right )^{2}\right]\left [n\sum{y}^{2} -\left (\sum{y}\right )^{2}\right]}}\\\\= \dfrac{9\times 1545776.75 - 9965\times 537.81}{\sqrt{[9\times 25569715 -9965^{2}][9\times 95799.63 - 537.81^{2}]}} \approx \mathbf{0.9879}$

(c) Regression line

The equation for the regression line is

y = a + bx where

$a = \dfrac{\sum y \sum x^{2} - \sum x \sum xy}{n\sum x^{2}- \left (\sum x\right )^{2}}\\\\= \dfrac{537.81\times 25569715 - 9965 \times 1545776.75}{9\times 25569715 - 9965^{2}} \approx \mathbf{-12.629}\\\\b = \dfrac{n \sum xy - \sum x \sum y}{n\sum x^{2}- \left (\sum x\right )^{2}} - \dfrac{9\times 1545776.75 - 9965 \times 537.81}{9\times 25569715 - 9965^{2}} \approx\mathbf{0.0654}\\\\\\\text{The equation for the regression line is $\large \boxed{\mathbf{y = -12.629 + 0.0654x}}$}$

(d) Residuals

Insert the values of x into the regression equation to get the estimated values of y.

Then take the difference between the actual and estimated values to get the residuals.

x y Estimated Residual

36 0.22 -10 10

67 0.62 -8 9

93 1.00 -7 8

142 1.86 -3 5

433 11.8 19 - 7

887 29.3 45 -16

1785 82.0 104 -22

2797 163.0 170 - 7

3675 248.0 228 20

(e) Suitability of regression line

A linear model would have the residuals scattered randomly above and below a horizontal line.

Instead, they appear to lie along a parabola (Fig. 2).

This suggests that linear regression is not a good model for the data.

4 0

3 years ago