Answer:
Step-by-step explanation:
Given the following lengths AB = 64, AM = 4x + 4 and BM= 6x-10, If M lies on the line AB then AM+MB = AB (addition property)
Substituting the given parameters into the addition property above;
AM+MB = AB
4x + 4 + 6x - 10 = 64
combine like terms
4x+6x = 64+10-4
10x = 74-4
10x = 70
Divide both sides by 10
x = 70/10
x = 7
Note that for M to be the midpoint of AB then AM must be equal to BM i.e AM = BM
To get AM ;
Since AM = 4x+4
substitute x = 7 into the function
AM = 4(7)+4
AM = 28+4
AM = 32
Similarly, BM = 6x-10
BM = 6(7)-10
BM = 42-10
BM = 32
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<em>Since AM = BM = 32,. then M is the midpoint of AB</em>
Answer:
The answer to your question is: 45° and 225°
Step-by-step explanation:
Getting tan⁻¹ 1 = 45°
Then, the angle we are looking for is 45°, let's check the for quadrangles.
First quadrangle = tan 45 = 1
Second quadrangle = 180° - 45° = 135° tan 135 = -1
Third quadrangle = 180 + 45 = 225° tan 225 = 1
Forth quadrangle = 360 - 45 = 315° tan 315° = -1
The answer is 2(x + 3)(x^2 + 1).
Steps:
2x^3 + 6x^2 + 2x + 6
2x^3 + 2x + 6x^2 + 6
2x(x^2 + 1) + 6(x^2 + 1)
(2x + 6)(x^2 + 1)
2(x + 3)(x^2 + 1)
I think the correct answer for that question is C
Y-4=1/5(x-7) is the answer
