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Alona [7]
3 years ago
11

What is the cube of the difference of 40 and a number

Mathematics
2 answers:
kogti [31]3 years ago
8 0

Answer:

The difference can be expressed as

y=x³+120x²-4800x+64000

Or

y=(40-x)³

Step-by-step explanation:

Step one

To solve the problem problem let us first initialize the number to be x

By breaking the statement into component parts and implementing

Step two

1. The difference between 40 and the number

=(40-x)

2. The cube of the difference

= (40-x)³

Let us equate the expression to y

y=(40-x)³

Step three

Expanding the expression we have

y= (40-x)(40-x)(40-x)

Opening bracket we have

y=(1600-40x-40x+x²)(40-x)

y=64000-1600x-

1600x+40x²-1600x+40x²+40x²-x³

y=x³+120x²-4800x+64000

tester [92]3 years ago
7 0

Answer:

(40-y)^3

Step-by-step explanation:

Make the unknown y

(40-y)^3

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spin [16.1K]

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Answer:

  448

Step-by-step explanation:

(4 pt/da)×(7 da/wk)×(16 oz/pt) = 448 oz/wk

That would be 448 fluid ounces per week.

3 0
3 years ago
Help me solve 18.4/2.3*3.4+13.812
dexar [7]
=(8)(3.4)+13.812
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the Answer is 41.012
7 0
3 years ago
(c + b + a) + (-2a - 3b + c)
inna [77]

━━━━━━━☆☆━━━━━━━

▹ Answer

<em>2c - 2b - a</em>

▹ Step-by-Step Explanation

(c + b + a) + (-2a - 3b + c)

<u>Remove the parentheses</u>

c + b + a + (-2a - 3b + c)

<u>Collect like terms</u>

2c + b + a - 2a - 3b

<u>Final Answer</u>

2c - 2b - a

Hope this helps!

- CloutAnswers ❁

Brainliest is greatly appreciated!

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7 0
3 years ago
Read 2 more answers
Find the equation of the locus of a point that moves so that its distance from the line 12x-5y-1=0 is always 1 unit.
leonid [27]

<u>Answer-</u>

The equations of the locus of a point that moves so that its distance from the line 12x-5y-1=0 is always 1 unit are

12x-5y+14=0 \\ 12x-5y-14=0

<u>Solution-</u>

Let a point which is 1 unit away from the line 12x-5y-1=0 is (h, k)

The applying the distance formula,

\Rightarrow \left | \frac{12h-5k-1}{\sqrt{12^2+5^2}} \right |=1

\Rightarrow \left | \frac{12h-5k-1}{\sqrt{169}} \right |=1

\Rightarrow \left | \frac{12h-5k-1}{13} \right |=1

\Rightarrow 12h-5k-1=\pm 13

\Rightarrow 12h-5k=\pm 14

\Rightarrow 12h-5k=14,\ 12h-5k=-14

\Rightarrow 12h-5k-14=0,\ 12h-5k+14=0

\Rightarrow 12x-5y-14=0,\ 12x-5y+14=0

Two equations are formed because one will be upper from the the given line and other will be below it.

4 0
3 years ago
What is the justification for each step in solving the inequality?
alekssr [168]
HELLO  ANNA!!

Given inequality
=> −2(x+1)≥3x+8
=>
- 2x - 2 \geqslant 3x + 8 \\ \\ add \: 2 \: in \: both \: sides \\ \\ - 2x \geqslant 3x + 10 \\ \\ subtract \: with \: - 3x \: in \: both \: sides \: \\ \\ - 5x \geqslant 10 \\

now multiply with - on both sides.

As we know now sign will change
=> 5x >_ -10

Now divide by 5 on both sides
=> x >_ -2
HOPE IT HELPED YOU.
4 0
3 years ago
Read 2 more answers
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