Answer:
2^20/3^8
Step-by-step explanation:
Answer:
<u>The correct answer is r = ∛GM*T²/4π²</u>
Step-by-step explanation:
Let's rewrite the formula to find the period of orbit of a satellite around a planet, to solve for r, this way:
T^2=(4pi^2/GM)r^3
T² = (4π²/GM) * r³
r³ = T²/ (4π²/GM)
r³ = T² * GM/4π²
r³ = GMT²/4π²
∛r³ = ∛GM*T²/4π²
r = ∛GM*T²/4π²
<u>The correct answer is r = ∛GM*T²/4π²</u>
It is basically the halfway through the circle
Answer:
14
Step-by-step explanation:
If you graph out the parabola, you look for the maximum height of the parabola and it is 14.
<span>Assume that,
x^2+4x-5 = 0 .......(1)
Then,
x^2+4x-5 = 0
x^2+5x-1x-5 =0
x(x+5)-1(x+5) = 0
(x+5) (x-1) = 0
We get x=-5 and x=1
Sub x=-5 in equ (1)
(-5)^2+4(5)-5 = 0
-25+20-5 = 0
-25+25= 0
0 = 0
Sub x=1 in equ (1)
(1)^2+4(1)-5 = 0
1+4-5 = 0
5-5 = 0
0 = 0
Therefore x value is -5 and 1</span>
