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2 years ago

Sam's car can travel 320 miles on 16 gallons of gas. Find the unit rate.

Mathematics

2 answers:

Snowcat [4.5K]2 years ago

8 0

Answer:I believe the answer is 20.

Step-by-step explanation:

Softa [21]2 years ago

5 0

The answer is 20 because 320/16 is 20

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Factor the expression 54x+81 using the GCF.

Vikki [24]

We are given the expression,

54x+81

Here we have to find Greatest Common Factor of 54 and 81

Factors of 54 are 1, 2, 3, 6, 9, 18 and 27.

Factors of 81 are 1, 3, 9, 27 and 81.

Greatest common factor of 54 and 81 is 27.

So we take out 27 common, rewriting the expression

27(2x+3)

Answer: 54x+81 in factored form equals 27(2x+3).

7 0

3 years ago

Read 2 more answers

En una competición participan 200 atletas, 2/5 son españoles, 1/3 del resto son franceses, 35 son alemanes y el resto son ingles

Bas_tet [7]

Answer:

7/40

Step-by-step explanation:

La fraccion de Alemanes son 35/200=7/40

6 0

3 years ago

At a cost of $8 per pound, how many ounces of rice flour can be bought for $3.35?

Lady_Fox [76]

Answer:

$41 cents

Step-by-step explanation:

$8 divided by $3.35 equals $0.41 cents

4 0

2 years ago

The length of a rectangle is 4 yd longer than its width. If the perimeter of the rectangle is 48 yd, find its area.

bagirrra123 [75]

48 = 2(w+4) + 2w
48 = 4w+8
40 = 4w
w= 10 yd
A= 10 * 14
A = 140 yd

7 0

2 years ago

Subtract fractions with different denominators

Tems11 [23]

Answer:

$\frac{10}{15}-\frac{2}{5}=\frac{4}{15}$

Step-by-step explanation:

We know that

A fraction consists of two integers—one on the top, and one on the bottom.
The top one is numerator, the bottom one is denominator, and
These two numbers are separated by a line.

Let us consider two different fractions with different denominators

$\frac{10}{15}$

$\frac{2}{5}$

Lets subtract the two fractions

$\frac{10}{15}-\frac{2}{5}\:\:\:\:$

$\mathrm{Cancel\:}\frac{10}{15}:\quad \frac{2}{3}$

$=\frac{2}{3}-\frac{2}{5}$

$\mathrm{Least\:Common\:Multiplier\:of\:}3,\:5:\quad 15$

$\mathrm{Adjust\:Fractions\:based\:on\:the\:LCM}$

$\mathrm{For}\:\frac{2}{3}:\:\mathrm{multiply\:the\:denominator\:and\:numerator\:by\:}\:5$

$\frac{2}{3}=\frac{2\cdot \:5}{3\cdot \:5}=\frac{10}{15}$

$\mathrm{For}\:\frac{2}{5}:\:\mathrm{multiply\:the\:denominator\:and\:numerator\:by\:}\:3$

$\frac{2}{5}=\frac{2\cdot \:3}{5\cdot \:3}=\frac{6}{15}$

$=\frac{10}{15}-\frac{6}{15}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$=\frac{10-6}{15}$

$\mathrm{Subtract\:the\:numbers:}\:10-6=4$

$=\frac{4}{15}$

Therefore,

$\frac{10}{15}-\frac{2}{5}=\frac{4}{15}$

5 0

2 years ago