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klio [65]
3 years ago
7

On Monday 4 bricklayers took 3 hours to lay a total of 4200 bricks.

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
7 0
<h2>Hello!</h2>

The answer is:

It will take 4.5 hours for two bricklayers to lay a total of 3150 bricks.

<h2>Why?</h2>

From the statement, we know that on Monday, bricklayers took 3 hours to lay a total of 4200 bricks.

So, we have that the rate of the four bricklayers is given by the following equation:

Production=Rate*Time\\\\Rate=\frac{Production}{time}

Rate=\frac{4200bricks}{3hours}=\frac{1400bricks}{hour}

Therefore, we have that the rate of the four bricklayers is 1400 bricks per hour, meaning that each bricklayer can lay 350 bricks per hour.

Now, to calculate how many hours it will take to the 2 bricklayers to lay a total of 3150, we need to divide the calculated rate (for bricklayers) by two, since there are only 2 bricklayers working on Tuesday.

So, calculating the time, we have:

Production=\frac{Rate}{2}*Time

3150bricks=\frac{\frac{1400bricks}{hour}}{2}*Time

3150bricks*2*\frac{1hour}{1400bricks}=Time

6300bricks*\frac{1hour}{1400bricks}=Time

Time=4.5hours

Hence, we have that it will take 4.5 hours for two bricklayers to lay a total of 3150 bricks.

Have a nice day!

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 1         -4
 2         -3
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The values (-4, -1), (-1, 2), (1, -4), (2, -3), (4, 3) expressed as a graph have been attached as graph_1


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There are lines joining from the circle labelled x to the circle labelled y with line joining -4 in circle x to -1 in circle y, -1 in circle x to 2 in circle y, 1 in circle x to -4 in circle y, 2 in circle x to -3 in circle y, 4 in circle x to  3 in circle y.

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2.) To express the values (-2, 1), (-1, 0), (1, 2), (2, -4), (4, 3) as a table, we have:

 x          y
-2         1
-1         0
 1          2
 2         -4
 4          3

The values (-2, 1), (-1, 0), (1, 2), (2, -4), (4, 3) expressed as a graph have been attached as graph_2


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The domain of the relation is the set of the x-values of the relation, i.e. domain is {-2, -1, 1, 2, 4}.
The range of the relation is the set of the y-values of the relation, i.e. range is {-4, 0, 1, 2, 3}
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