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ELEN [110]
3 years ago
6

There were 340,000 cattle placed on bead write an equivalent ratio that could be used to find how many of these cattle were betw

een 700 and 799 pounds how many of the 340,000 cattle placed on feed wire between 700 and 799 pounds
Mathematics
1 answer:
Olin [163]3 years ago
5 0
170,000 FEED POUNDS....
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Factor sec^2x-secx+tan^2x
marysya [2.9K]

Answer:

sec²(x) - sec(x) + tan²(x) = (sec(x) - 1)(2sec(x) + 1)

Step-by-step explanation:

sec²(x) - sec(x) + tan²(x) =

= sec²(x) - sec(x) + [sec²(x) - 1]

= sec²(x) - sec(x) + [(sec(x) + 1)(sec(x) - 1)]

= sec(x)[sec(x) - 1] + [(sec(x) + 1)(sec(x) - 1)]

= (sec(x) - 1)(sec(x) + sec(x) + 1)

= (sec(x) - 1)(2sec(x) + 1)

6 0
3 years ago
Is 4/3y=x a direct variation?
Masja [62]

Answer:

1 yes 2 no 3 no

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
DOES ANYONE KNOW HOW TO DO THIS????????
castortr0y [4]

Answer:

1. figure 4

2. Figure 1

3. Figure 3

Step-by-step explanation:

1. r is the degree of the line or group of dots that makes a line. for r=1, the line is going to be as close to a linear line as possible. the dots will be close together a make either a close or perfect straight line. This is why we pick figure 4, because the points are decently close together and form a positive slope.

2. a linear relationship can be tested by a straight line test, and in this case you pick the figure that fails the test the most. in this case, Figure 1 fits.

3.  looking for r=-1 is looking for the opposite of r=1, so since figure 3 is the opposite of figure 4, we know it fits the description

4 0
3 years ago
Any body know the answers to these
snow_lady [41]
For 3. he answer is a
for 4 the answer is two
6 0
3 years ago
Point M is the midpoint of AB. The coordinates of point A are (-8, 3) and the coordinates of M are (-2, 1). What are the coordin
ch4aika [34]

Answer:

the coordinates of point B are (-5, 2)

Step-by-step explanation:

1. use midpoint formula to find the midpoint (equation attached below)

2. plug in the numbers

(\frac{-8+(-2)}{2},\frac{3+1}{2})

3. solve

(\frac{-8-2)}{2},\frac{3+1}{2})

(\frac{-10}{2},\frac{4}{2})

(-5,2})

4 0
2 years ago
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