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denpristay [2]
3 years ago
8

Plz dont skip and answer. Will give branliest. No links please

Mathematics
2 answers:
marta [7]3 years ago
7 0

Answer:

Step-by-step explanation:

So first off. lets take chunks of this shape. We have a 6x8 rectangle, a 4x5 rectangle, and a 1/4 circle with a radius of 12.

The area of a rectnagle is just length x width.

So lets plug in our values for our two ractnagles, and see what we get:

6*8

=

48

So our first rectangle has a area of 48

Next we have:

4*5

=

20

So our second rectangle has an area of 20.

Add these otgether you get 68.

Finally we have our 1/4 circle. To solve this, find the area of the full circle and divide by 4.

We already know the radius, which is 12, and the formula for area of a circle is:

a=πr^2

Plug in 12:

a=π12^2

=

a=π144

dividing by four for the 1/4circle:

a=π36

So this means your answer is either:

68 +36π

Or:

181.097(solving pi*36)

Either of these work, if the problem allows pi, then use the first one, If not, use the bottom one.

Hope this helps!

Aneli [31]3 years ago
4 0

Answer:

181 mi^2

Step-by-step explanation:

Dimensions of large rectangle, on the left, are 6 mi by 8 m; area is 48 m^2;

Dimensions of small rectangle, in the middle of the diagram, are 4 mi by 5 mi, or 20 mi^2; area is 20 mi^2.

Dimensions of circle:  r = 12 mi; area of quarter circle is (1/4)(3.14)(12 mi)^2, or 113 mi^2.

Total area is 113 mi^2 + 20 mi^2 + 48 mi^2, or 181 mi^2

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S = 2B + L. What do S, B, and L stand for?
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3 years ago
A rectangular parking lot has a perimeter of 820 ft. The area of the parking lot measure SL 42,000 ft
horsena [70]

Answer:

a= 200

b = 210

Step-by-step explanation:

My assumption is, we have to find the length of sides of rectangle

Given

perimeter = 2a + 2b = 820 ft (i) (here a is smaller side and b is larger side)

area = a*b = 42,000 ft^2 (ii)

from eq (1)

2a + 2b = 820

=> 2(a+b) = 820

=> a+b = 820/2

=> a + b = 410

=> a = 410-b   (iii)

putting the value of a in eq(ii), we get

(410-b) *b = 42,000

410b - b^2 = 42,000

0 = b^2 - 410b + 42000

b^2 - 410b + 42000 = 0

b^2- 200b- 210b + 42000 = 0

b(b-200)-210(b-200) = 0

(b-200)(b-210) = 0

or

b= 210 and b = 200

if b is larger side than b =210

By putting value of b in eq(iii),

a = 410 -210 = 200

 

6 0
3 years ago
Solve the equation 4(x + 2)= 6x + 4
SIZIF [17.4K]

The answer is x=2

show you step-by-step

step 1:simplify both sides of the equation.

(4)(x)+(4)(2)=6x+4

4x+8=6x+4

step 2:subtract 6x from both sides.

4x+8-6x=6x+4-6x

-2x+8=4

step 3: subtract 8 from both sides

-2x+8-8=4-8

-2x=-4

step 4: divide both sides by -2

-2x/-2= -4/-2

x=2

that helps you


7 0
3 years ago
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