Can someone help me

The value of a car decreases by 1/6 every year. What type of function represents this patten

PolarNik [594]

Answer:

Exponential decay

Step-by-step explanation:

the answer is not linear decrease cause the price doesn't decrease the same every year

.. ..

4 0

3 years ago

The population of Hermitville increased from 142,340 to 186,480 in the last 5 years. During the same time period, Crabville incr

Musya8 [376]

The rate of increase of population of Hermitville is given by:
PR=(Present Population-Past Population)/(Past population)*100
PR=(186480-142340)/142340×100
PR=31.01%
The population increase in Hermitville is 31.01;
This implies that it's population growth is faster than that of Crabville by a factor of
31.01/26=1.19.
The answer is B

5 0

4 years ago

Read 2 more answers

Find 16% of 25 litres

Svetllana [295]

Answer: 4

Step-by-step explanation:

(16/100) × 25

= 4

Therefore, 16% of 25 litres is 4 litres.

3 0

3 years ago

Find the equation for the trend line through the points (0, 11) and (100, 33). Then use it to predict the number of baskets Romy

sleet_krkn [62]

Answer:

28 baskets

Step-by-step explanation:

The equation for a linear trend line is given by:

y = mx + b, where y and x are variables, m is the slope of the line and b is the y intercept (that is value of y when x is zero).

The equation of a line passing through two points $(x_1,y_1)\ and\ (x_2,y_2)$ is:

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

y represent the number of baskets made and x represents the time take. Given that the line passes through the points (0, 11) and (100, 33), hence:

$y-11=\frac{33-11}{100-0}(x-0)\\\\y-11=\frac{11}{50}x\\\\y= \frac{11}{50}x+11$

The number of baskets Romy would make after practicing for 80 minutes (x = 80) is:

$y=\frac{11}{50}x+11\\\\y=\frac{11}{50}(80)+11 \\\\y=17.6+11\\\\y=28.6\\\\Therefore\ y\ =\ 28\ baskets$

5 0

3 years ago

11. There are eleven seniors and five juniors who are sprinters on the high school track team. The coach must select four sprint

nirvana33 [79]

Answer:

a) 1820

b) 55

c) 10

d) 550

e) 0.3022

Step-by-step explanation:

Data provided in the question:

Number of seniors = 11

Number of juniors = 5

n = number of choices

r = number of person to be selected

number of ways = $^nC_r$

a) 4-sprinter relay teams can be formed from the group of 16 sprinters

n = 16

r = 4

= ¹⁶C₄

= $\frac{16!}{4!(16-4)!}$

= $\frac{16\times15\times14\times13\times12!}{4\times3\times2\times1(12!)}$

=

b) two seniors be chosen to be part of the relay team

n = 11

r = 2

= ¹¹C₂

= $\frac{11!}{2!(11-2)!}$

= $\frac{11\times10\times9!}{2\times1(9!)}$

=

c) two juniors be chosen to be part of the relay team

n = 5

r = 2

= ⁵C₂

= $\frac{5!}{2!(5-2)!}$

= $\frac{5\times4\times3!}{2\times1(3!)}$

= 10

d) two seniors and two juniors be chosen to be part of the relay team

= two seniors be chosen to be part of the relay team × two juniors be chosen to be part of the relay team

= 55 × 10

= 550

e) P( two seniors and two juniors will be chosen for the relay team )

= [ two seniors and two juniors be chosen to be part of the relay team ] ÷ [4-sprinter relay teams can be formed from the group of 16 sprinters ]

= 550 ÷ 1820

= 0.30219 ≈ 0.3022

6 0

4 years ago