Can't see it the equation is to blurry.
Rectangle
l = 7.2 - 1.7 = 5.5 ft b = 3.4 ft
Semicircle
r = 1.7 ft
Shaded region = area of rectangle + area of semicircle
= l x b + πr²/2
= 5.5 x 3.4 + 3.14 x 1.7 x 1.7 x 1/2
= 18.7 + 4.5373
= 23.2373 ft²
V =

r^2h/3
V = 3.14 x 4^2 x 6/3 (remember r is 1/2 of the diameter)
V = 3.14 x 16 x 2
V = 100.5
<span>Simplifying
6(x + -1) = 9(x + 2)
Reorder the terms:
6(-1 + x) = 9(x + 2)
(-1 * 6 + x * 6) = 9(x + 2)
(-6 + 6x) = 9(x + 2)
Reorder the terms:
-6 + 6x = 9(2 + x)
-6 + 6x = (2 * 9 + x * 9)
-6 + 6x = (18 + 9x)
Solving
-6 + 6x = 18 + 9x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-9x' to each side of the equation.
-6 + 6x + -9x = 18 + 9x + -9x
Combine like terms: 6x + -9x = -3x
-6 + -3x = 18 + 9x + -9x
Combine like terms: 9x + -9x = 0
-6 + -3x = 18 + 0
-6 + -3x = 18
Add '6' to each side of the equation.
-6 + 6 + -3x = 18 + 6
Combine like terms: -6 + 6 = 0
0 + -3x = 18 + 6
-3x = 18 + 6
Combine like terms: 18 + 6 = 24
-3x = 24
Divide each side by '-3'.
x = -8
Simplifying
x = -8</span>
This is an incomplete question, here is a complete question and image is also attached below.
How much longer is the hypotenuse of the triangle than its shorter leg?
a. 2 ft
b. 4 ft
c. 8 ft
d. 10 ft
Answer : The correct option is, (b) 4 ft
Step-by-step explanation:
Using Pythagoras theorem in ΔACB :


Given:
Side AC = 6 ft
Side BC = 8 ft
Now put all the values in the above expression, we get the value of side AB.



Now we have to calculate the how much longer is the hypotenuse of the triangle than its shorter leg.
Difference = Side AB - Side AC
Difference = 10 ft - 6 ft
Difference = 4 ft
Therefore, the 4 ft longer is the hypotenuse of the triangle than its shorter leg.