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3 years ago

What is the point slope form for a slope 6 and points -9,5

Mathematics

1 answer:

const2013 [10]3 years ago

8 0

Answer:

y - 5 = 6(x + 9)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Here m = 6 and (a, b) = (- 9, 5), thus

y - 5 = 6(x - (- 9)), that is

y - 5 = 6(x + 9)

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Inga [223]

Answer:

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2 years ago

A student writes the equation for a line that has a slope of -6 and passes through the point (2, –8).

allochka39001 [22]

If you wrote this in point-slope form, it’ll be y+8=-6(x-2).

This equation written in slope intercept form would be y = -6x+4.

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3 years ago

Factor Completely: 3x2 + 9x - 30

enyata [817]

Answer:

3(x-2)(x+5)

Step-by-step explanation:

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2. Factor (x^2 +3x-10)

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4 years ago

Greg invests $500 in a savings account that earns 4% simple interest annually. If he does not make any additional deposits or wi

Stella [2.4K]

Answer:

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Step-by-step explanation:

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3 years ago

h(x)= \dfrac{1}{8} x^3 - x^2h(x)= 8 1 x 3 −x 2 h, left parenthesis, x, right parenthesis, equals, start fraction, 1, divided b

Nesterboy [21]

Answer:

$\dfrac{1}{2}$

Step-by-step explanation:

Given the function $h(x)=\dfrac{1}{8}x^3-x^2$

The average rate of change of the function h(x) over the interval $a\le x\le b$ can be calculated using formula

$\dfrac{h(b)-h(a)}{b-a}$

In your case,

$a=-2,\\ \\b=2,$

so the average rate of change is

$\dfrac{h(2)-h(-2)}{2-(-2)}\\ \\=\dfrac{(\frac{1}{8}\cdot 2^3-2^2)-(\frac{1}{8}\cdot (-2)^3-(-2)^2)}{4}\\ \\=\dfrac{(1-4)-(-1-4)}{4}\\ \\=\dfrac{-3+5}{4}\\ \\=\dfrac{2}{4}\\ \\=\dfrac{1}{2}$

6 0

3 years ago