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makkiz [27]
3 years ago
15

Graph the line that passes through (2,5), parallel to the graph of 1.4x 8.5y=-3

Mathematics
1 answer:
lions [1.4K]3 years ago
8 0
Turn the eqation into slope intercept form (y=mx+b)
solve 4 y
graph it
then plot your points and make it parrellel
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Someone answer this question I know your reading this.
IgorC [24]

Answer: A.

Step-by-step explanation:

To answer this, you must first understand what fractional exponents mean.

An exponent of 1 is simply the base itself. 7^1 = 7.

An exponent of 2 is squaring the base: 7^2 = 49.

An exponent of 1/2 is taking the square root of the base: 7^(1/2) = sq root of 7

Therefore, an exponent of 1/3 is taking the cube root of the base.

In this case, the base is 2.03 * t.

Therefore, this can be represented as the cube root of the product of 2.03 and the age of the mammal, so the answer is A.

3 0
3 years ago
What is bigger 0.7liters or 500 millileters​
Mkey [24]

Answer:

0.7 Ls

Step-by-step explanation:

A liter (L) and a milliliter (mL) are two units for measuring capacity in the metric system. The bottle pictured at the right holds 1 L of water. About twenty drops of water equals 1 mL. To convert liters to milliliters, To convert milliliters to liters, multiply by 1,000.

5 0
3 years ago
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F(x)=3/5x+1 find f(-15)
Luda [366]
Nothing hahahahahah
3 0
3 years ago
A polygon with 3 vertices is drawn on the coordinate plane. What can you tell about the polygon?
Rus_ich [418]

Answer:

triangle

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Step-by-step explanation:

5 0
3 years ago
Select the expression that is equivalent to: 3 root 1089
Delicious77 [7]

Answer:

3\sqrt{1089}=3\sqrt{3^2(11)^2}

Step-by-step explanation:

Given : Expression 3\sqrt{1089}

To find : Select the expression that is equivalent to expression ?

Solution :

Re-write the expression as,

3\sqrt{1089}=3\sqrt{3\times 3\times 11\times 11}

3\sqrt{1089}=3\sqrt{3^2\times 11^2}

3\sqrt{1089}=3\sqrt{(3\times 11)^2}

3\sqrt{1089}=3\sqrt{(33)^2}

3\sqrt{1089}=3\times 33

3\sqrt{1089}=99

The above are the possible equivalent expressions.

7 0
3 years ago
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