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3 years ago

15

a wooden fruit crate will hold 62 pounds of fruit. the crate already has 18 pounds of fruit in it. which inequality represents t

he solution set that shows the pounds of fruits ,p, that can be added to the crate

1 answer:

tatuchka [14]3 years ago

7 0

Answer:

$p + 18 \leq 62$

Step-by-step explanation:

Given

$Total = 62\ lb$

$Current = 18\ lb$

Required

Write an inequality to represent the scenario?

Represent the additional number of pounds with p.

When p is added to the current pounds, the weight must be less than or equal to the total possible weights

In other words:

$p + current \leq total$

Substitute values for current and total

$p + 18 \leq 62$

Hence, the inequality that describes the scenario is: $p + 18 \leq 62$

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3 years ago

a corner shelf is 1/4 of a circle and has a radius of 10.5 inches . Enter the area of the shelf in square inches . round your an

schepotkina [342]

First, find the area of the shelf if it were a full circle.
the formula for the area of a circle is a=pi(r squared)
a=pi (10.5 squared)
a=pi x 110.25
a=3.14 x 110.25
a=346.185
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5 0

3 years ago

A small company can produce up to 200 handmade sandals a month. The monthly cost, C, of producing x sandals is C(x) = 1000 + 5x.

wariber [46]

<span>I will assume the more likely selection of $10 per sandal as opposed to $0.05 per sandal. So with the formulas c = 1000 + 5x r = 75x - 0.4x^2 Sandals Cost Revenue Profit or Loss 0 $1,000.00 $0.00 -$1,000.00 1 $1,005.00 $74.60 -$930.40 2 $1,010.00 $148.40 -$861.60 3 $1,015.00 $221.40 -$793.60 4 $1,020.00 $293.60 -$726.40 5 $1,025.00 $365.00 -$660.00 6 $1,030.00 $435.60 -$594.40 7 $1,035.00 $505.40 -$529.60 8 $1,040.00 $574.40 -$465.60 9 $1,045.00 $642.60 -$402.40 10 $1,050.00 $710.00 -$340.00 11 $1,055.00 $776.60 -$278.40 12 $1,060.00 $842.40 -$217.60 13 $1,065.00 $907.40 -$157.60 14 $1,070.00 $971.60 -$98.40 15 $1,075.00 $1,035.00 -$40.00 16 $1,080.00 $1,097.60 $17.60 17 $1,085.00 $1,159.40 $74.40 18 $1,090.00 $1,220.40 $130.40 19 $1,095.00 $1,280.60 $185.60 20 $1,100.00 $1,340.00 $240.00 As you can see 16 sandals and up is profitable. At what production levels will the company lose money? a. between 0 and 10 or between 150 and 190 pairs, inclusive 150 and 190 c. between 10 and 20 or between 50 and 100, inclusive If you add up the profit between 10 and 20 you will get $-484 so 50 and 100 b. between 0 and 15 or between 160 and 200 pairs, inclusive 160 and 200 d. between 15 and 35 or between 75 and 125, inclusive Neither 15 and 35 or 75 and 125 will lose money.</span>

3 0

3 years ago

The estimated daily living costs for an executive traveling to various major cities follow. The estimates include a single room

Alexandra [31]

Answer:

$\bar x = 260.1615$

$\sigma = 70.69$

The confidence interval of standard deviation is: $53.76$ to $103.25$

Step-by-step explanation:

Given

$n =20$

See attachment for the formatted data

Solving (a): The mean

This is calculated as:

$\bar x = \frac{\sum x}{n}$

So, we have:

$\bar x = \frac{242.87 +212.00 +260.93 +284.08 +194.19 +139.16 +260.76 +436.72 +355.36 +.....+250.61}{20}$

$\bar x = \frac{5203.23}{20}$

$\bar x = 260.1615$

$\bar x = 260.16$

Solving (b): The standard deviation

This is calculated as:

$\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n-1}}$

$\sigma = \sqrt{\frac{(242.87 - 260.1615)^2 +(212.00- 260.1615)^2+(260.93- 260.1615)^2+(284.08- 260.1615)^2+.....+(250.61- 260.1615)^2}{20 - 1}}$ $\sigma = \sqrt{\frac{94938.80}{19}}$

$\sigma = \sqrt{4996.78}$

$\sigma = 70.69$ --- approximated

Solving (c): 95% confidence interval of standard deviation

We have:

$c =0.95$

So:

$\alpha = 1 -c$

$\alpha = 1 -0.95$

$\alpha = 0.05$

Calculate the degree of freedom (df)

$df = n -1$

$df = 20 -1$

$df = 19$

Determine the critical value at row $df = 19$ and columns $\frac{\alpha}{2}$ and $1 -\frac{\alpha}{2}$

So, we have:

$X^2_{0.025} = 32.852$ ---- at $\frac{\alpha}{2}$

$X^2_{0.975} = 8.907$ --- at $1 -\frac{\alpha}{2}$

So, the confidence interval of the standard deviation is:

$\sigma * \sqrt{\frac{n - 1}{X^2_{\alpha/2} }$ to $\sigma * \sqrt{\frac{n - 1}{X^2_{1 -\alpha/2} }$

$70.69 * \sqrt{\frac{20 - 1}{32.852}$ to $70.69 * \sqrt{\frac{20 - 1}{8.907}$

$70.69 * \sqrt{\frac{19}{32.852}$ to $70.69 * \sqrt{\frac{19}{8.907}$

$53.76$ to $103.25$

8 0

2 years ago

Leonardo da vinci took out A simple interest loan at 12.75% interest for 12 months. His previous balance is % 942.36. What is hi

makkiz [27]

Answer:

A = 2,384.1708

Step-by-step explanation:

A = P(1 + rt)

P = 942.36

r = 12.75%

t = 12 months

A = 942.36(1 + 12.75/100(12))

A = 942.36(2.53)

A = 2,384.1708

6 0

3 years ago