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nataly862011 [7]

3 years ago

10

Need help with this. Can you please tell me the answer to this?

2 answers:

VladimirAG [237]3 years ago

7 0

It’s (5+x) and (5-x)

Alex787 [66]3 years ago

5 0

Answer:

(5+x)(5-x)

Step-by-step explanation:

5^2-x^2, simplified.

Difference of squares formula= a^2-b^2=(a+b)(a-b)

5^2-x^2=(5+x)(5-x).

<h2>Please vote as Brainliest!</h2>

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I’m super confused on what this means

vampirchik [111]

The two triangles are congruent to each other, meaning they’re proportional to each other but not equal.
The question is asking you to list the angles that are congruent to each other (when talking about angles and congruency, if two angles are congruent, they are equal) and the sides that are congruent to each other (as long as all sides are proportional to each other, they are congruent (Triangle ABC has side lengths of 1, 2, 3 and Triangle DEF has side lengths of 2, 4, 6; these two triangles are congruent))

3 0

3 years ago

The khan's car averages 22 miles per gallon of gas. predict how far they can travel on 5 gallons of gas.

Viefleur [7K]

They can travel roughly 110 miles for 5 gallons of gas.

4 0

3 years ago

Read 2 more answers

Exercise 5.2. Suppose that X has moment generating function

soldi70 [24.7K]

Answer:

a) Mean, E(X) = - 0.5

Variance = = 9.25

b) $M_{X}(t)=E(e^{tX})$

or

⇒ $=\sum e^{tx}p(x)$

⇒ $=\frac{1}{2}+\frac{1}{3}e^{-4t}+\frac{1}{6}e^{5t}$

Step-by-step explanation:

Given:

moment generating function of X as:

MX(t) = $\frac{1}{2} + \frac{1}{3}e^{-4t} + \frac{1}{6} e^{5t}$

a) Now

Mean, E(X) = $M_{X}'(t=0)$

Thus,

$M_{X}'(t)=\frac{1}{3}(-4)e^{-4t}+\frac{1}{6}(5)e^{5t}$

or

$M_{X}'(t)=\frac{-4}{3}e^{-4t}+\frac{5}{6}e^{5t}$

also,

$E(X^{2})=M_{X}''(t=0)$

Thus,

$M_{X}''(t)=\frac{-4}{3}(-4)e^{-4t}+\frac{5}{6}(5)e^{5t}$

or

$M_{X}''(t)=\frac{16}{3}e^{-4t}+\frac{25}{6}e^{5t}$

Therefore,

Mean, E(X) = $M_{X}'(t=0)=\frac{-4}{3}e^{-4(0)}+\frac{5}{6}e^{5(0)}$

or

Mean, E(X) = - 0.5

and

$E(X^{2})=M_{X}''(t=0)=\frac{16}{3}e^{-4(0)}+\frac{25}{6}e^{5(0)}$

or

$E(X^{2})$ = 9.5

also,

Variance(X) = E(X²) - E(X)²

⇒ 9.5 - (-0.5)²

= 9.25

b) Now,

Let f(x) be the PMF of X

Thus,

$M_{X}(t)=E(e^{tX})$

or

⇒ $=\sum e^{tx}p(x)$

⇒ $=\frac{1}{2}+\frac{1}{3}e^{-4t}+\frac{1}{6}e^{5t}$

Therefore,

at x = 0, P(x) = $\frac{1}{2}$

at x= - 4 ,P(x) = $\frac{1}{3}$

at x = 5, P(x) = $\frac{1}{6}$

Thus,

E(X) = $\sum xP(x)=0(\frac{1}{2})+(-4)(\frac{1}{3})+5(\frac{1}{6})$

or

E(X) = - 0.5

also, $E(X^{2})=\sum x^{2}P(x)=0^{2}(\frac{1}{2})+(-4)^{2}(\frac{1}{3})+5^{2}(\frac{1}{6})$

$E(X^{2})$ = 9.5

Hence,

Var(X) = E(X²) - E(X)²

⇒ 9.5 - (-0.5)²

= 9.25

4 0

4 years ago

The bar chart shows all the eye colours of students in a class. What fraction of the students have blue eyes? Give your answer i

Burka [1]

Answer:

1/29

Step-by-step explanation:

There are 29 students in total, and the students with blue eyes is only 1.

The fraction would be 1/29 and this is its simplest form.

5 0

3 years ago

Help meeeeeeee please

Len [333]

Answer:

x=-20

Step-by-step explanation:

x-3/4x=3/10x-1

20x-15x=6x+20

5x=6x+20

5x-6x=20

-x=20

x=-20

6 0

3 years ago