4 years ago

The Kp for the reaction below is 1.49 × 108 at 100.0 °C:

1 answer:

8 0

The equilibrium constant in this case is [CO2]/[Cl2][CO]. Given the Kp, we can get directly the partial pressure of phosgene which is 1.49x10^8*1x10^-4*1x10^-4. This is equal to 1.49 atm.

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