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3 years ago

Which statement represent an abiotic environmental factor in an ecosystem?

1 answer:

5 0

The answer would be D. (The 4th one listed).
Abiotic factors are the non-living parts of the environment that can often have a major influence on living organisms.
Hope this helps!

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What is smaller? WHY? a Atom or Electron

tresset_1 [31]

Electron, because they’re about 1/2000 the mass of a proton or nuetron

6 0

3 years ago

What are the rows of the periodic table of the elements also called?

lesya [120]

The rows are called Periods.

4 0

3 years ago

Read 2 more answers

What is 190 K in degrees Celsius? Show your work for full credit.

saveliy_v [14]

Answer:

-83.15

Explanation:

190K − 273.15 = -83.15°C

3 0

2 years ago

How many grams are in 4.5 x 10^22 molecules of Ba(NO2)2

NNADVOKAT [17]

Answer:

17 g Ba(NO₂)₂

General Formulas and Concepts:

Chemistry

Stoichiometry
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

Step 1: Define

4.5 × 10²² molecules Ba(NO₂)₂

Step 2: Define conversion

Molar Mass of Ba - 137.33 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Ba(NO₂)₂ - 137.33 + 2(14.01) + 4(16.00) = 229.35 g/mol

Step 3: Dimensional Analysis

$4.5 \cdot 10^{22} \ mc \ Ba(NO_2)_2(\frac{1 \ mol \ Ba(NO_2)_2}{6.022 \cdot 10^{23} \ mc \ Ba(NO_2)_2} )(\frac{229.35 \ g \ Ba(NO_2)_2}{1 \ mol \ Ba(NO_2)_2} )$

= 17.1384 g Ba(NO₂)₂

Step 4: Check

We are given 2 sig figs. Follow sig fig rules.

17.1384 g Ba(NO₂)₂ ≈ 17 g Ba(NO₂)₂

7 0

2 years ago

The answer to question 2

Bad White [126]

Answer:

Explanation:

You will need a chemical equation with masses and molar masses, so let’s gather all the information in one place.

$M_{r}$ : 258.21 18.02

KAl(SO₄)₂·xH₂O ⟶ KAl(SO₄)₂ + xH₂O

Mass/g: 4.74 2.16

Step 1. Calculate the mass of the KAl(SO₄)₂.

Mass = 4.74 g – 2.16 g = 2.58 g.

Step 2. Calculate the moles of each product.

$\text{Moles of KAl(SO}_{4})_{2} = \text{2.58 g} \times \frac{\text{1 mol} }{\text{258.21 g}} = 9.992 \times 10^{-3} \text{ mol}$

$\text{Moles of H}_{2}\text{O} = \text{2.16 g} \times \frac{\text{1 mol} }{\text{18.02 g}} = \text{ 0.1200 mol}$

Step 3. Calculate the molar ratio of the two products.

$\frac{\text{Moles of KAl(SO}_{4})_{2}}{\text{Moles of H}_{2}\text{O}} = \frac{ 9.992 \times 10^{-3} \text{ mol}}{\text{ 0.1200 mol} } = \frac{1 }{12.01} \approx \frac{ 1}{ 12}$

1 mol of KAl(SO₄)₂ combines with 12 mol H₂O, so x = 12.

3 0

3 years ago