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hram777 [196]
3 years ago
12

What was the open-range system ​

Chemistry
1 answer:
Nesterboy [21]3 years ago
5 0

Answer: In the Western United States and Canada, open range is rangeland where cattle roam freely regardless of land ownership. ... Land in open range that is designated as part of a "herd district" reverses liabilities, requiring an animal's owner to fence it in or otherwise keep it on the person's own property.

Explanation: Mark me as brainliest

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Can anyone help me with this asap?
tresset_1 [31]

Answer:

Explanation:

1) During the diagnosis of thyroid disease a 10 g sample of I-131 is used. After a period of 32 days, how much sample is still radio active.?

Answer:

0.625 g

Explanation:

HL = Elapsed time/half life

32 days/8 days = 4

At time zero = 10 g

At 1st half life = 10/2 = 5 g

At 2nd half life = 5/2 = 2.5 g

At 3rd half life = 2.5 /2 = 1.25 g

At 4th half life = 1.25 / 2 = 0.625 g

After 32 days still 0.625 g of I-131 remain radioactive.

2) what was the original mass of sample Tc-99 that was used to locate the brain tumor If 0.10 g of a sample remains after 30 days? (half life 6 days)

Answer:

0.32 g.

Explanation:

Half life = time elapsed / HL

Half life = 30 days / 6 days = 5

At 5th half life = 0.10 g

At 4th half life = 0.2 g

At 3rd half life =  0.4 g

At 2nd  half life = 0.8 g

At 1st half life = 0.16 g

At time zero = 0.32 g

The original amount was 0.32 g.

3) write the beta decay equation of I-131?

Equation:

¹³¹I₅₃  →  ¹³¹Xe₅₄ + ⁰₋₁e

Beta radiations are result from the beta decay in which electron is ejected. The neutron inside of the nucleus converted into the proton an thus emit the electron which is called β particle.

The mass of beta particle is smaller than the alpha particles.

They can travel in air in few meter distance.

These radiations can penetrate into the human skin.

The sheet of aluminium is used to block the beta radiation

¹³¹I₅₃  →  ¹³¹Xe₅₄ + ⁰₋₁e

The beta radiations are emitted in this reaction. The one electron is ejected and neutron is converted into proton.

3 0
3 years ago
Calcium reacts with oxygen to form calcium oxide. the chemical equation for this reaction is ca + o2 → cao. what is the product,
natka813 [3]

In any balanced chemical reaction, the elements or compounds which are located in the left hand side of the arrow is the reactants while those that are location on the right hand side are the products, therefore the product here is:

<span>CaO or Calcium Oxide</span>

3 0
4 years ago
The following reaction has been reported in the chemical literature and gives a single organic product in high yield. Write the
Alla [95]

Answer:

Explanation:

The principle applied is the Markovnikoff's rule which states that when hydrogen chloride adds to a double bond, the hydrogen atoms join to the carbon that already has the most hydrogen atoms bonded to it. The rule wa postulated by a russian chemist known as Vladimir Markovnikoff.

In the markovnikoff's rule, there are sveral conditions that must be met, one of them is that no free radicals must be involved.

The reaction and the structure of the product is as shown in the attachment.

8 0
3 years ago
Select the correct answer.
Sladkaya [172]

Answer:

  • <u><em>Option D. There will be a shift toward the reactants.</em></u>

Explanation:

The reaction is:

       PCl_5(g)+heat\rightleftharpoons PCl_3(g)+Cl_2(g)

The application of LeChatelier's principle leads to consider the <em>heat</em> as a <em>reactant</em> or a product depending on if it is on the left side or the right side.

In this reaction, the <em>heat</em> is on the left side, thus it must be considered a <em>reactant</em>.

Decreasing the temperature is equivalent to remove or consume heat. Thus, the reaction must shif to the left to compensate that reduction of heat. That is the reverse reaction shall be favored.

In conclusion, <em>there will be a shift toward the reactants.</em>

5 0
3 years ago
From the unbalanced reaction: B2H6 + O2 ---&gt; HBO2 + H2O
Drupady [299]

Answer: 125 g

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} B_2H_6=\frac{36.1g}{17}=1.30moles

The balanced reaction is:

B_2H_6+3O_2\rightarrow 2HBO_2+2H_2O

According to stoichiometry :

1 mole of B_2H_6 require = 3 moles of O_2

Thus 1.30 moles of B_2H_6 will require=\frac{3}{1}\times 1.30=3.90moles  of O_2

Mass of O_2=moles\times {\text {Molar mass}}=3.90moles\times 32g/mol=125g

Thus 125 g of O_2 will be needed to burn 36.1 g of B_2H_6

4 0
3 years ago
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