Answer:
Answer:
safe speed for the larger radius track u= √2 v
Explanation:
The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.
Also given that r_1= smaller radius
r_2= larger radius curve
r_2= 2r_1..............i
let u be the speed of larger radius curve
now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=
r
1
mv
2
=
r
2
mu
2
................ii
form i and ii we can write
v^2= \frac{1}{2} u^2v
2
=
2
1
u
2
⇒u= √2 v
therefore, safe speed for the larger radius track u= √2 v
Answer: 14
Step-by-step explanation:
20% of 60=12
20% of 10=2
12+2=14
1000ft > 300 yd
1ft=3yd
1000ft=333.33yd
I got 16,000 tubes are sold in half a day because there are 720 minutes in 12 hours, and 43,200 seconds in 720 minutes then you divide by 2.7 and get 16,000
B
i think with is the correct ansuer
