Write the statement as an equation." Three is subtracted from the reciprocal of a number. Let x be equal to the number .

Suppose you invest $1400 at interest rate of 4.3% compounded continuously. How much will you have in the account after 7 years?

STatiana [176]

$\bf ~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$1400\\ r=rate\to 4.3\%\to \frac{4.3}{100}\dotfill &0.043\\ t=years\dotfill &7 \end{cases} \\\\\\ A=1400e^{0.043\cdot 7}\implies A=1400e^{0.301}\implies A\approx 1891.69\implies \stackrel{\textit{rounded up}}{A=1892}$

3 0

3 years ago

The owner of a small pet supply store wants to open a second store in another city, but he only wants to do so if more than one-

Andrei [34K]

Answer:

The answer is "The null hypothesis was rejected".

Step-by-step explanation:

Following are the right-tailed test:

Calculating the null and alternative hypothesis:

$H_0 : p = 0.3333\\\\H_a : p > 0.3333\\\\n = 150\\\\x = 64\\\\\hat{p} = \frac{x}{n} = \frac{64}{150} = 0.4267\\\\P_0 = 0.3333\\\\1 - P_0 = 1 - 0.3333 = 0.6667\\\\$

$z = \frac{\hat{p} - P_0}{[\sqrt{\frac{P_0 \times (1 - P_0 )}{n}}]}$

$= \frac{0.4267 - 0.3333}{[\sqrt{\frac{(0.3333 \times 0.6667)}{150}}]}\\\\= 2.426$

Calculating the right-tailed test:

$P(z > 2.426) = 1 - P(z < 2.426) = 1 - 0.9924 = 0.0076\\\\P-value = 0.0076\\\\\alpha = 0.05\\\\P-value < \alpha$

Therefore, we reject the null hypothesis.

This example shows that more than a third of the families own pets in this town.

5 0

2 years ago

Consider the functions f(x)=x−7 and g(x)=4x^3.

maxonik [38]

Answer:

I think A is correct

7 0

3 years ago

Twenty different books are to be put on five book shelves, each of which holds at least twenty books.

olya-2409 [2.1K]

Answer:

(a) 10,626 different arrangements

(b) 95,367,431,640,625 different arrangements

(c) 2.5852017 × 10²² different arrangements

Step-by-step explanation:

(a) How many different arrangements are there if you only care about the number of books on the shelves (and not which book is where)?

We use the combination formula for this

C(n , r) = n + r - 1C r - 1

n = 20

r = 5

= 20 + 5 - 1 C 5-1

= 24C4

= 24!/4 ! × (24 - 4)

= 24!/4! × 20!

= 10,626 arrangements

(b) How many different arrangements are there if you care about which books are where, but the order of the books on the shelves doesn't matter?

Since the order of the books on the shelves does not matter,

The calculation is given as

5²⁰ = 95,367,431,640,625 arrangements

(c) How many different arrangements are there if the order on the shelves does matter?

Since order matters now

Step 1

We use the combination formula for this

C(n , r) = n + r - 1C r - 1

n = 20

r = 5

= 20 + 5 - 1 C 5-1

= 24C4

= 24!/4 ! × (24 - 4)

= 24!/4! × 20!

= 10,626

Step 2

We find the factorial of the number books

= 20!

= 2,432,902,008,176,640,000

Step 3

The different arrangements there are if the order on the shelves does matter is calculated

= 10,626 × 2,432,902,008,176,640,000

= 2.5852017 × 10²² different arrangements

8 0

3 years ago

A plane leaves town A for town B.at 0540hours.If the journey takes 6.5hours at what time does the plane reach its destination?

Oliga [24]

The plane reaches its destination at 12h10 minutes if the plane leaves town A for town B.at 0540hours

For legal, commercial, and social purposes, a time zone is a region that observes a uniform standard time. Instead of strictly following longitude, time zones tend to follow the borders between countries and their subdivisions.

We have:

A plane leaves town A for town B.at 0540hours.If the journey takes 6.5hours

05h40min

Total time takes = 6 hours and 30 minutes

= 5 hours + 40 minutes + 6 hours + 30 minutes

= 11 hours + 70 minutes

= 12 hours 10 minutes

or

= 12h10 minutes

Thus, the plane reaches its destination at 12h10 minutes if the plane leaves town A for town B.at 0540hours

Learn more about the time zone here:

brainly.com/question/10711315

#SPJ1

5 0

1 year ago