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Rina8888 [55]
3 years ago
7

My mom is 38 inches tall her mom is 5 feet tall how many inches taller is her mom

Mathematics
1 answer:
dedylja [7]3 years ago
3 0
She is 22 inches long!!!
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Rachel has 5 cups of flour she needs 1/3 cup of flour for one jumbo muffin how many jumbo muffins can she make ​
Anvisha [2.4K]

Answer:

15 jumbo muffins.

Step-by-step explanation:

If you need 1/3 cups of flour for each jumbo muffin and have 5 cups of flour. Multiply 3 and 5 which will give you 15 which is how many jumbo muffins you can make.

3 0
4 years ago
Please help me with these 19 and 20 and tell me what you use to get the answer
ss7ja [257]
36 + h = 75...subtract 36 from both sides
h = 75 - 36
h = 39

-176 = h + (-219)
-176 = h - 219....add 219 to both sides
219 - 176 = h
43 = h
6 0
3 years ago
Read 2 more answers
On Tuesday the value of a stock decreased by 1/2 point. On Wednesday, the value increased by 3/4 point. On Thursday the value de
Tpy6a [65]
The change is -(1/2 + 3/4 + 3/8).
If you add the fractions, you get -(13/8).
3 0
3 years ago
Wich one of the following items is an exmple of software?
saul85 [17]
A) Word-processing program is an example of a software
6 0
3 years ago
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Find the equation of a line that is perpendicular to y = 3x – 5 and passes through the point (1, -3).
Svetradugi [14.3K]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

\begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad \qquad y = \stackrel{\stackrel{m}{\downarrow }}{3}x-5

well then therefore

\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{3\implies \cfrac{3}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{3}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{3}}}

so we're really looking for the equation of a line with slope of -1/3 and that passes through (1, -3 )

(\stackrel{x_1}{1}~,~\stackrel{y_1}{-3})\qquad \qquad \stackrel{slope}{m}\implies -\cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{-\cfrac{1}{3}}(x-\stackrel{x_1}{1})\implies y+3=-\cfrac{1}{3}x+\cfrac{1}{3} \\\\\\ y=-\cfrac{1}{3}x+\cfrac{1}{3}-3\implies y=-\cfrac{1}{3}x-\cfrac{8}{3}

6 0
2 years ago
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