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enyata [817]
2 years ago
12

Barry and Robin walk to Dunkin' Donuts each Saturday to meet for coffee and donuts. Barry walks the 2 miles from his house in 30

minutes and Robin walks the 3 miles from his house in 36 minutes.
Find the unit rate in minutes per mile for Barry.
Find the unit rate in minutes per mile for Robin.
Who walks faster, Barry or Robin?
Mathematics
1 answer:
lbvjy [14]2 years ago
6 0

Answer:

Barry travels 4mph. Robin travels 5mph. Therefore Robin is walking faster.

Step-by-step explanation:

2x2=4

36/60=0.6

0.2=1

0.2x5=1

1x5=5

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An online store holds a sale.Of the 500 customers who make a purchase during the sale,60 use a coupon.What percent of the custom
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Answer:

88%

Step-by-step explanation:

60/500 people use a coupon

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What is the equation of the line that is parallel to the line 2x+3y=-8 and passes through the point (2,-2)?
Leya [2.2K]

Equation of line passing through (2, -2) and parallel to 2x+3y = -8 is y=\frac{-2 x}{3}+\frac{-2}{3}

<h3><u>Solution:</u></h3>

Need to write equation of line parallel to 2x+3y=-8 and passes through the point (2, -2)

Generic slope intercept form of a line is given by y = mx + c

where "m" = slope of the line and "c" is the y - intercept

Let’s first find slope intercept form of 2x+3y=-8 to get slope of line

\begin{array}{l}{2 x+3 y=-8} \\\\ {=>y=\frac{-2 x-8}{3}} \\\\ {\Rightarrow y=-\frac{2}{3} x-\frac{8}{3}}\end{array}

On comparing above slope intercept form of given equation with generic slope intercept form y = mx + c,

\text {for line } 2 x+3 y=-8, \text { slope } m=-\frac{2}{3}

We know that slopes of parallel lines are always equal

So the slope of line passing through (2, -2) is also m=-\frac{2}{3}

Equation of line passing through (x_1 , y_1) and having slope of m is given by

\left(y-y_{1}\right)=\mathrm{m}\left(x-x_{1}\right)

\text { In our case } x_{1}=2 \text { and } y_{1}=-2

Substituting the values in equation of line we get

(y-(-2))=-\frac{2}{3}(x-2)

\begin{array}{l}{\Rightarrow y+2=\frac{-2 x+4}{3}} \\\\ {=>3(y+2)=-2 x+4} \\\\ {=>3 y+6=-2 x+4} \\\\ {3 y=-2 x-2}\end{array}

y=\frac{-2 x}{3}+\frac{-2}{3}

Hence equation of line passing through (2 , -2) and parallel to 2x + 3y = -8 is given as y=\frac{-2 x}{3}+\frac{-2}{3}

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