Maximum because it contains quartile one 3 and the media
Answer:
Step-by-step explanation:
You are to make 5 assemblies.
Each assembly requires the use of 1 Type A bolt.
To make the 5 assemblies, you need 5 Type A bolts.
The container of bolts has a total of 60 bolts.
The focus - Type A bolts - is 20 out of this 60.
The probability of obtaining a Type A bolt at all, is 20/60, which is = 1/3
(A) What is the probability of taking the exact number of Type A bolts you need for your 5 assemblies, if you randomly take 10 bolts from the container?
- The exact number of Type A bolts you need for the 5 assemblies is 5
1/3 × 5/10 = 5/30 = 1/6 = 0.167
(B) What is the probability of taking/having less than 5 Type A bolts out of the randomly selected 10 bolts? The solution is to sum up the following:
1/3 × 4/10 = 0.133
1/3 × 3/10 = 0.1
1/3 × 2/10 = 0.067
1/3 × 1/10 = 0.033
1/3 × 0/10 = 0
TOTAL = 0.333
Answer:
x² - 12x + 27
Step-by-step explanation:
(f + g)(x)
= f(x) + g(x)
= x² - 13x + 36 + x - 9 ← collect like terms
= x² - 12x + 27 ← in standard form
Answer:
Just switch out the 6 and 4 flip them out I guess
Step-by-step explanation:
Answer:
8 9.8 - 6.4n
9 15 - j/2
Step-by-step explanation:
8
2.8 - 4.4n - 2n +7
= 2.8+7 -4.4n -2n
= 9.8 - 6.4n
9
11 + (-3) - 1/8 j - 3/8 j +7
= 11 - 3 - 1/8 j - 3/8 j + 7
= 11 - 3 + 7 - 1/8 j - 3/8 j
= 15 - 4/8 j
= 15 - j/2
