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kogti [31]
3 years ago
5

Many bedbugs are highly resistant to insecticides, but the scientist’s bedbugs aren’t resistant. Explain why this happens based

on environment and selection of genes.
Biology
1 answer:
Nutka1998 [239]3 years ago
4 0

Wild Bedbugs become insecticide resistant because of the mutations and natural selections.

<h3><u>Explanation</u>:</h3>

As the huge amount of pesticides and insecticides are sprayed in the rooms for cleaning, the pests and insects like bedbugs dies in huge portions because of the toxin. But some of the bedbugs remain alive as they have mutations that help them to detoxify the toxins given, or bypass the metabolic processes so that the toxins don't hamper them much.

Now as the population becomes very small(bottle neck effect), the nature selects these organisms over the other to propagate more sufficiently and enormously. As the nutrients and supplies are also available, so the bedbugs don't suffer any lack of nutrition which can be a determining factor of their population.

Thus the wild bedbugs become resistant to insecticides while the experimental one remain succeptible to insecticides.

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alexandr1967 [171]

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<u>C. Broca's Area</u>

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g If a person takes a prescribed dose of 10 milligrams of Valium, the amount of Valium in that person's bloodstream at any time
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Answer:

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Explanation:

If a person takes a prescribed dose of 10 milligrams of Valium, the amount of Valium in that person's bloodstream at any time can be modeled by

A_{t}=10e^{-0.0173t}

Where A(t) = amount of Valium remaining in the blood after t hours

t = time or duration after the drug is taken

a. we have to calculate the amount of drug remaining in the bloodstream after 12 hours

A_{12}=10e^{-0.0173\times12}

A_{12}=10e^{-0.2076}

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b. In this part we have to calculate the time when A(t) = 5 milligrams

5=10e^{-0.0173\timest}

\frac{5}{10}=e^{-0.0173t}

0.5 = e^{-0.0173t}

Now we take natural log on both the sides of the equation.

ln(0.5) = ln(e^{-0.0173t})

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t = \frac{0.69314}{0.0173}

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c. In this part we have to calculate the rate, by which amount of drug will decay in the bloodstream after 7 hours.

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A_{7}=10e^{-0.1211}

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Answer:

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