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3 years ago

Solve for k: 8k + 2m=3m+4

Mathematics

1 answer:

Andreyy893 years ago

6 0

Isolate the k. Note the equal sign. What you do to one side, you do to the other.

First, subtract 2m from both sides

8k + 2m (-2m) = 3m (-2m) + 4

8k = m + 4

Next, divide 8 from both sides

(8k)/8 = (m + 4)/8

k = (m + 4)/8

k = m/8 + 1/2

k = m/8 + 1/2 is your answer

hope this helps

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Answer:

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Step-by-step explanation:

First consider the slope of this equation we must derive;

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So far we can formulate an equation as such;

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3 years ago

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3 years ago

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3 years ago

Read 2 more answers

the length of a rectangle is 5 times as long as its breadth and its area is 1620 m² find area of square whose perimeter is equal

Rus_ich [418]

Answer:

Area of the square is 2916 $m^{2}$ .

Step-by-step explanation:

Let the breadth of the rectangle be represented by w. So that;

length of rectangle = 5w

Area of rectangle = length x breadth

= 5w x w

1620 = 5 $w^{2}$

divide through by 5 to have,

$w^{2}$ = 324

w = $\sqrt{324}$

= 18

Thus, the breadth of the rectangle is 18 m.

length = 5 w = 5 x 18

= 90 m

The length of the rectangle is 90 m.

Perimeter of the rectangle = 2(l + w)

= 2( 90 + 18)

= 216 m

Perimeter of a square = 4l

where l is the length of its side.

Given that the perimeters of the rectangle and square are equal, then;

4l = 216

l = $\frac{216}{4}$

= 54

length of the side of square is 54 m.

Therefore,

Area of square = $l^{2}$

= $54^{2}$

= 2916

Area of the square whose perimeter is equal to that of the rectangle is 2916 $m^{2}$ .

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3 years ago