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nika2105 [10]
3 years ago
15

On a calendar of 31 days what are the prime numbers

Mathematics
2 answers:
Ugo [173]3 years ago
6 0
2<span>, </span>3<span>, </span>5<span>, </span>7,13 ,29<span>, </span><span>31 hope this helps :)</span>
zepelin [54]3 years ago
5 0
I believe <span>2   3   5   7   11   13   17   19   23   29   31</span>
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A rectangle on a coordinate plane is translated 5 units up and 3 units to the left. Which rule describes the trar
Citrus2011 [14]

Answer:

(x, y) → (x - 3, y + 5 )

Step-by-step explanation:

A shift of 3 units to the left means subtract 3 from the original x- coordinate.

A shift of 5 units up means add 5 to the original y- coordinate.

Thus the rule representing the translation is

(x, y ) → (x - 3, y + 5 )

6 0
3 years ago
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Solve for j. -1j+1&gt;2<br> Please help.
prohojiy [21]
You can use photomath for this
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3 years ago
suppose A and B are complementary angles, m a =(3x+5) and m b= (2x-15). Solve for x and then find m a and m b
vlada-n [284]
2 angles are complementary if the sum of their measures is 90°.

For example  if m(P) = 41°  and m(Q)=49°, then P and Q are complementary.


Thus A and B are complementary means that m(A)=m(B)=90°:

(3x+5°) + (2x-15°) =90°

5x-10°=90°

5x=100°

x=20°



Thus 

m(A)=3x+5°=3* 20°+5°=60°+5°=65°

m(B)=2x-15°=2*20°-15°=40°-15°=25°
8 0
3 years ago
I need help asap please
kakasveta [241]

Answer:

1. 1570

2. can't see properly

3. can't see properly

4. 392.5

5. 615.4

6. 6049

7. not clear can't see

8. 1589

9.:1570

3 0
3 years ago
Find the perimeter of the polygon with the vertices g(2, 4), h(2,−3), j(−2,−3), g(2, 4), h(2,−3), j(−2,−3), and k(−2, 4)k(−2, 4)
Julli [10]
<span>The distance between g and h is sqrt[(2-2)^2+(4+3)^2]=7 The distance between h and j is sqrt[(2+2)^2+(-3+3)^2]=4 The distance between j and k is sqrt[(-2+2)^2+(-3-4)^2]=7 The distance between k and g is sqrt[(-2-2)^2+(4-4)^2]=4 The perimeter of the polygon is 7+4+7+4=22</span>
7 0
3 years ago
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