The actual skate park's perimeter is 130 inches.
Explanation:
Step 1; Assume the initial garden has a width of y inches. It is given that the length is 25 inches. The perimeter of any given rectangle is twice the sum of the length and the width of the same rectangle. The initial perimeter is given as 80 inches.
Perimeter = 2 × (length of the rectange + width of the rectangle).
80 = 2 × (25 + y), 40 = 25 + y, y = 40 - 25 = 15
So the initial park has a width of 15 inches.
Step 2; Now we calculate the actual skate park's perimeter. The length is given as 50 inches and the width was found to be 15 inches.
Perimeter = 2 × (length of the rectange + width of the rectangle).
Perimeter = 2 × (50 + 15) = 2 × 65 = 130 inches.
Answer:
the answer is 9.69 or if no decimals 10
Step-by-step explanation:
24% of 242 is 58.08 you then divide that number with 6/ the amount of points they get every touchdown. you divide those numbers and you get 9.69.
and that's the amount of points they got but if there aren't any decimals in this question then it would be closer to 100 than it would be 0 so the answer is 10 points
i hope this helped. :)
<h3>
Answer: 16 square units</h3>
Let x be the height of the parallelogram. Right now it's unknown, but we can solve for it using the pythagorean theorem. Focus on the right triangle. It has legs a = 3 and b = x, with hypotenuse c = 5
a^2 + b^2 = c^2
3^2 + x^2 = 5^2
9 + x^2 = 25
x^2 = 25-9
x^2 = 16
x = sqrt(16)
x = 4
This is a 3-4-5 right triangle.
The height of the parallelogram is 4 units.
We have enough info to find the area of the parallelogram
Area of parallelogram = base*height
Area of parallelogram = 4*4
Area of parallelogram = 16 square units
Coincidentally, the base and height are the same, which isn't always going to be the case. The base is visually shown as the '4' in the diagram. The height is the dashed line, which also happens to be 4 units long.
Answer brother this not maths question
Step-by-step explanation:
Answer: 10
Step-by-step explanation:
By definition, the point at which a median intersects the side of the triangle opposite from the vertex from which it is drawn is the midpoint of that side.
