<h3>Answer:</h3>
It depends:
- 4 if she starts at 4
- 5 if she starts at 0
<h3>Explanation:</h3>
Louise needs to end up a total of 5 times 4 away from zero.
If she starts at 4, which is 1 times 4, then she needs to jump 4 more times, to 2, 3, 4, 5 times 4.
If she starts at 0, then she needs to jump 5 times to 1, 2, 3, 4, 5 times 4. (The values at the end of each jump will be {4, 8, 12, 16, 20}.)
Answer:
0.6708 or 67.08%
Step-by-step explanation:
Helen can only make both free throws if she makes the first. The probability that she makes the first free throw is P(C) = 0.78, now given that she has already made the first one, the probability that she makes the second is P(D|C) = 0.86. Therefore, the probability of Helen making both free throws is:

There is a 0.6708 probability that Helen makes both free throws.
The answer for this problem would be 7x+6
Let's solve this problem step-by-step.
4x−3+3x+9
=4x+−3+3x+9
Step 1: Combine Like Terms.
=4x+−3+3x+9
=(4x+3x)+(−3+9)
So, the answer for this problem would be 7x+6.
Answer:
z=24 y=5 x=12
Step-by-step explanation:
x+8=20 x=20-8 x=12
z+1=25 z=25-1 z=24
y+10=15 y=15-10 y=5