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sergij07 [2.7K]
3 years ago
8

Which of the following equations could be used to solve for the tenth term of the following sequence? 15, 13, 11, 9, ...

Mathematics
2 answers:
Darya [45]3 years ago
6 0

Answer:

Equations that could be used to solve for the tenth term of the sequence:

15, 13, 11, 9, ...    is  

b) A(10) = 15 + 9(-2)

Step-by-step explanation:

We are given a sequence:

 15,13,11,9,...

The above sequence is an arithmetic progression with

first term=A(1)=15 and common difference=d=-2

Now, the nth term of an arithmetic progression is determined by the formula

A(n)= A(1)+(n-1)d

⇒  A(10)=  15+9(-2)

Hence, the correct option is:

  b) A(10) = 15 + 9(-2)

omeli [17]3 years ago
4 0

Answer

b) A(10) = 15 + 9(-2)


<u>Explanation</u>

15, 13, 11, 9, ...  This is an arithmetic sequence.

The common difference = 13 - 15 = -2

                                     or = 9 - 11 = -2

The first term of the sequence = 15.

The nth term of an arithmetic sequence is given by:

Tn = a + (n - 1)d

∴ T₁₀ = 15 + (10 - 1)(-2)

        = 15 + (9 × -2)  ⇒ This is the expression you need.

        = 15 + -18

       = -3

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What solution do 2x2 - 13x + 21 = 0 and 2x2 + 9x - 56 = 0 have in common? Round your answer to the nearest tenth if necessary.
lys-0071 [83]
So if we want to know the common solution(s) to a system of 2 equations, So we can just set both equations equal to each other and solve for the x value(s). That’s where I start below;

2x^2-13x+21 = 2x^2+9x-56
2x^2 cancels out and moving everything to one side and anything with an x variable to the other side we have then;
-22x=-77
22x=77 by cancelling the negative signs
x=77/22 therefore x=7/2 or 3.5

Hope this helps you. Any questions please ask.
4 0
3 years ago
Caden removed the label of a soup can like the one shown. What is the approximate area of the label if the can is 4 inches high
Dominik [7]

EXPLANATION

If the height of the can is 4 inches and the diameter is 3--> radius=1.5 inches, the area is given by the following relationhip:

\text{Area}_{\text{label}}=2\pi rh

Replacing terms:

\text{Area}_{\text{label}}=2\pi\cdot1.5\cdot4=12\pi=37.7in^2

The approximate area is 37.7 in^2

5 0
1 year ago
May someone help, please ? Thank you ♥️
koban [17]
My final answer is (C) because for the side lenghts to be a right triangle, the values of the first and second terms should be equal to the third (a^2 and b^2 =c^2) hope that helped (:
3 0
3 years ago
Romb ma obwód równy 32 cm. Jakie jest pole tego rombu, jeżeli jego wysokość ma 3 cm?
Goshia [24]

Answer:

24 cm²

Step-by-step explanation:

Z zadanego powyżej pytania uzyskano następujące dane:

Obwód (obwód) = 32 cm

Wysokość (h) = 3 cm

Obszar rombu (A) =?

Następnie określimy długość boku rombu. Można to uzyskać w następujący sposób:

Obwód, czyli obwód (P) = 32 cm

Strona (y) =?

P = 4 s

32 = 4 s

Podziel obie strony przez 4

s = 32/4

s = 8 cm

Stąd długość boku rombu wynosi 8 cm

Na koniec określimy obszar rombu w następujący sposób:

Długość boków = 8 cm

Wysokość (h) = 3 cm

Obszar rombu (A) =?

A = sh

A = 8 × 3

A = 24 cm²

Dlatego obszar rombu jest

24 cm².

8 0
3 years ago
One restaurant uses 5 quarts of soup to make 20 equal servings. Another restaurant uses 7 quarts of soap to make 25 equal servin
rjkz [21]
20/5=4
25/7=<span>3.57142857143 Rounded to the nearest tenth: 3.6
4>3.6
If you want the nearest whole, you would round down to 3 because you would be short of 4.
3<4 </span>
5 0
3 years ago
Read 2 more answers
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