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vovikov84 [41]
3 years ago
15

Julie Ann works on an assembly line building computers. She can assemble 8 units an hour. Write an expression for the number of

units she can produce in h hours. Question 2 options: h ÷ 8 h - 8 8 + h 8h
Mathematics
1 answer:
kykrilka [37]3 years ago
8 0

Answer:

Number of units=H(8)

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The main show tank has a radius of 60 feet and forms a quarter sphere where the bottom of the pool is spherical and the top of t
svetlana [45]

The given radius is = 60 feet

The volume of the sphere is given by = \frac{4}{3} \pi r^{3}

So we will find the volume of the sphere using radius as 60 and pi as 3.14

Volume = \frac{4}{3}*3.14*60*60*60 = 902059.20 cubic feet

As quarter of anything is defined as its one-fourth part, so here the volume of the quarter of sphere can be calculated by finding one fourth of the calculated volume.

So volume of quarter sphere = \frac{902059.20}{4}

= 225514.80 cubic feet

And rounding this to nearest whole number we get 225515 cubic feet as the answer.


3 0
3 years ago
A rectangular swimming pool is twice as long as it is wide. A small concrete walkway surrounds the pool. The walkway is a 2 feet
Ksivusya [100]

Answer:

The width and the length of the pool are 12 ft and 24 ft respectively.

Step-by-step explanation:

The length (L) of the rectangular swimming pool is twice its wide (W):

L_{1} = 2W_{1}

Also, the area of the walkway of 2 feet wide is 448:

W_{2} = 2 ft

A_{T} = W_{2}*L_{2} = 448 ft^{2}

Where 1 is for the swimming pool (lower rectangle) and 2 is for the walkway more the pool (bigger rectangle).

The total area is related to the pool area and the walkway area as follows:

A_{T} = A_{1} + A_{w}    (1)          

The area of the pool is given by:

A_{1} = L_{1}*W_{1}        

A_{1} = (2W_{1})*W_{1} = 2W_{1}^{2}  (2)          

And the area of the walkway is:

A_{w} = 2(L_{2}*2 + W_{1}*2) = 4L_{2} + 4W_{1}    (3)          

Where the length of the bigger rectangle is related to the lower rectangle as follows:                  

L_{2} = 4 + L_{1} = 4 + 2W_{1}   (4)        

By entering equations (4), (3), and (2) into equation (1) we have:

A_{T} = A_{1} + A_{w}

A_{T} = 2W_{1}^{2} + 4L_{2} + 4W_{1}                

448 = 2W_{1}^{2} + 4(4 + 2W_{1}) + 4W_{1}            

224 = W_{1}^{2} + 8 + 4W_{1} + 2W_{1}

224 = W_{1}^{2} + 8 + 6W_{1}

By solving the above quadratic equation we have:

W₁ = 12 ft

Hence, the width of the pool is 12 feet, and the length is:

L_{1} = 2W_{1} = 2*12 ft = 24 ft

Therefore, the width and the length of the pool are 12 ft and 24 ft respectively.

I hope it helps you!                                                                                          

8 0
3 years ago
3 Ximena draws an X shape in the coordinate plane as shown. Draw the images of
VARVARA [1.3K]

When a shape is rotated, it must be rotated around a point.

<em>See attachment for the image of each rotation.</em>

To do this, the top coordinates of the X shape will be transformed using the appropriate rotation rule; the same rule will then be applied to the other parts of the X shape.

The top coordinates of the X shape are:

A = (0,0)

B = (1,0)

C = (3,0)

D =(4,0)

For 90 degrees counterclockwise rotation, the rule is:

(x,y) \to (-y,x)

So, we have:

A' = (0,0)

B' = (0,1)

C' = (0,3)

D' = (0,4)

For 180 degrees rotation, the rule is:

(x,y) \to (-x,-y)

So, we have:

A' = (0,0)

B' = (-1,0)

C' = (-3,0)

D' = (-4,0)

For 270 degrees counter rotation, the rule is:

(x,y) \to (y,-x)

So, we have:

A' = (0,0)

B' = (0,-1)

C' = (0,-3)

D' = (0,-4)

See attachment for the image of each rotation

Read more about rotations at:

brainly.com/question/1571997

3 0
3 years ago
Solve for y: 76y = 19
Lena [83]

Answer:

y = 1/4 = 0.250.

Step-by-step explanation:

4 0
3 years ago
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What’s the area of a circle if the diameter is 80
aleksley [76]

The area of a circle if the diameter is 80 is

A=5026.55

8 0
3 years ago
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