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3 years ago

What is a synonym for the number 11

Mathematics

2 answers:

Alika [10]3 years ago

8 0

Prime number because it has no factors .

Doss [256]3 years ago

7 0

Maybe prime number considering that 11 has no other factors. Hope I helped

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For which product or quotient is this expression the simplest form? (image attached)! please help :((

mars1129 [50]

Answer:

Step-by-step explanation:

For simplify the work we can start to factorise all the possibles expressions:

2x + 8.

8 is multiple of 2, so it can became

2(x+4)

x^2 - 16 this is a difference of two squares, so it can be rewritten as:

(x+4)(x-4)

x^2 + 8x + 16

we have to find two numbers whose sum is 8 and whose product is 16

the two number are 4 and 4

it becames:

(x+4)(x+4)

x+ 4 can‘t be simplified

if we look at the expression, we can find that x-4 appears at the numerator so

x^2 - 16 must be at numerator

but the second factor (x+4) doesn’t appear, so has been simplified. This situation can be possible only in the D option

in fact

(x+4)(x-4)/2(x+4) * (x+4)/(x+4)(x+4)

it became

(x+4)(x-4)/2 * 1/(x+4)(x+4)

(x-4)/2(x+4)

4 0

3 years ago

Hey I need help a lot of help

Neko [114]

30
6 times 5 is 30 and since its 6 per hour you just do it to five :)

4 0

3 years ago

Read 2 more answers

Help me please this is a test ASAP 30 points ???

Serga [27]

Answer:

$\frac{2}{3}x-4\frac{2}{3}$

3 0

3 years ago

Read 2 more answers

Four boys weighed themselves in different pairs and alone. The weights of the pairs were 110 kg, 112 kg, 113 kg, 118 kg, 121 kg,

brilliants [131]

The lost pair of weight can be found by subtracting the a known pair from

the total weight leaving the value of the lost pair.

The lost weight of a pair of boys is 120 kg

Reasons:

Let a, b, c, and d represent the weights of the four boys, we have;

The number of ways of selecting pairs (two boys) of boys from a group of

four is given using combination formula as follows;

$_nC_r = \dfrac{n!}{r! \cdot (n - r)!}$

Which gives;

$_4C_2 = \dfrac{4!}{2! \cdot (4 - 2)!} = 6$

₄C₂ = 6

Therefore, the weights of the pairs are;

a + b = 110

a + c = 112

a + d = 113

b + c = 118

b + d = 121

c + d = Lost weight

c + d = Lost weight

a + b + c + d = 230 (given)

Therefore;

The lost weight, c + d = 230 - (a + b)

Which gives;

c + d = 230 - (110) = 120

The lost weight = c + d = 120

The lost weight = 120 kg

Learn more here:

brainly.com/question/12974932

6 0

3 years ago

Read 2 more answers

Plz give answer fast.

maks197457 [2]

Answer:

plz mark brainliest✌️✌️

3 0

3 years ago