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3 years ago

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Five members of the soccer team ordered orange juice. Ten members ordered apple juice. Juice was packaged in 250 mL cartons. Exp

lain how to calculate how many more milliliters of apple juice than orange juice were ordered. A. Step 1 Multiply: 250 × 5. Step 2 Multiply: 250 × 10. Step 3 Add the products. B. Step 1 Multiply: 250 × 5. Step 2 Multiply: 250 × 10. Step 3 Subtract the products. C. Step 1 Divide: 250 ÷ 5. Step 2 Divide: 250 ÷ 10. Step 3 Subtract the quotients. D. Step 1 Divide: 250 ÷ 5. Step 2 Divide: 250 ÷ 10. Step 3 Add the quotients.

2 answers:

insens350 [35]3 years ago

8 0

B. is the answer i am sure hope it helps

Gnoma [55]3 years ago

6 0

Its b . i hope this helps

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Solve the oblique triangle where side a has length 10 cm, side c has length 12 cm, and angle beta has measure thirty degrees. Ro

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Answer:

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The missing angles are $\alpha = 56.2$ and $\theta = 93.8$

Step-by-step explanation:

Given

$A = 10\ cm$

$C = 12\ cm$

$\beta = 30$

The implication of this question is to solve for the missing side and the two missing angles

Represent

Angle A with $\alpha$

Angle B with $\beta$

Angle C with $\theta$

Calculating B

This will be calculated using cosine formula as thus;

$B^2 = A^2 + C^2 - 2ACCos\beta$

Substitute values for A, C and $\beta$

$B^2 = 10^2 + 12^2 - 2 * 10 * 12 * Cos30$

$B^2 = 100 + 144 - 240 * 0.8660$

$B^2 = 100 + 144 - 207.8$

$B^2 = 36.2$

Take Square root of both sides

$B = \sqrt{36.2}$

$B = 6.0$ <em>(Approximated)</em>

Calculating $\alpha$

This will be calculated using cosine formula as thus;

$A^2 = B^2 + C^2 - 2BCCos\alpha$

Substitute values for A, B and C

$A^2 = B^2 + C^2 - 2BCCos\alpha$

$10^2 = 6^2 + 12^2 - 2 * 6 * 12 * Cos\alpha$

$100 = 36 + 144 - 144Cos\alpha$

Collect Like Terms

$100 - 36 - 144 = -144Cos\alpha$

$-80 = -144Cos\alpha$

Divide both sides by -144

$\frac{-80}{-144} = Cos\alpha$

$0.5556 = Cos\alpha$

$\alpha = cos^{-1}(0.5556)$

$\alpha = 56.2$ <em>(Approximated)</em>

Calculating $\theta$

This will be calculated using cosine formula as thus;

$C^2 = B^2 + A^2 - 2BACos\theta$

Substitute values for A, B and C

$12^2 = 6^2 + 10^2 - 2 * 6 * 10Cos\theta$

$144 = 36 + 100 - 120Cos\theta$

Collect Like Terms

$144 - 36 - 100 = -120Cos\theta$

$8 = -120Cos\theta$

Divide both sides by -120

$\frac{8}{-120} = Cos\theta$

$-0.0667= Cos\theta$

$\theta = cos^{-1}(-0.0667)$

$\theta = 93.8$ <em>(Approximated)</em>

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andrey2020 [161]

Answer:

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Step-by-step explanation:

The expression that we have to evaluate in this problem is:

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$7x^{-3}y^{-1}=\frac{7}{x^3 y}$

Now we observe that:

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Step-by-step explanation:

1. The problem asked for the product of $\frac{2}{5}a^{2}x$ and $-\frac{1}{5}x^{2}a$ , therefore, you must mutliply them, as you can see below:

2. According the exponents propertiess, when you have a multiplication of two powers that has the equal base, you must add the exponents. THerefore, you have the following result:

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