Question

Write the equation of the line that passes through the point (-5,5) and has a slope of -8/5

Answer 1

Answer:

The equation of the line that passes through the point (-5,5) and has a slope of -8/5 will be:

                                           $y=-\frac{8}{5}x-3$

Step-by-step explanation:

Given

• $\left(x_1,\:y_1\right)=\left(-5,5\right)$

• $m=\frac{-8}{5}$

Point-Slope Form equation is

$\left(y-y_1\right)=m\left(x-x_1\right)$

$\left(y-5\right)=\frac{-8}{5}\left(x-\left(-5\right)\right)$

$\mathrm{Apply\:rule}\:-\left(-a\right)=a$

$y-5=\frac{-8}{5}\left(x+5\right)$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}$

$y-5=-\frac{8}{5}\left(x+5\right)$

$y-5+5=-\frac{8}{5}\left(x+5\right)+5$

$y=-\frac{8}{5}x-3$

Therefore, the equation of the line that passes through the point (-5,5) and has a slope of -8/5 will be:

                                           $y=-\frac{8}{5}x-3$