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3 years ago

Are these similar ?

Mathematics

1 answer:

Ksju [112]3 years ago

4 0

Answer:

Yes, by S-A-S

Step-by-step explanation:

Angle M and Angle A are congruent, and the labeled sides are proportionate to each other so they are similar.

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Vertices A (-1,1) and Vertices B (-4,1) of Square ABCD are shown below. What is the perimeter?

Pani-rosa [81]

Answer:

Step-by-step explanation:

Distance from (-4,1)to (-1,1) =|-4|-|-1|=3

Side of square =3

Since each side of square is equal.

3x4=12

5 0

3 years ago

Whats the square root of 196/14

PilotLPTM [1.2K]

Answer:

if you mean the square root of 196 divided by 14

then that equals 14 and the square root of 14 is

3.74

Step-by-step explanation:

4 0

3 years ago

1. The mechanics at Lincoln Automotive are reborning a 6 in deep cylinder to fit a new piston. The machine they are using increa

Firdavs [7]

Answer:

$0.0239\frac{in^{3}}{min}$

Step-by-step explanation:

In order to solve this problem, we must start by drawing a diagram of the cylinder. (See attached picture)

This diagram will help us visualize the problem better.

So we start by determining what data we already know:

Height=6in

Diameter=3.8in

Radius = 1.9 in (because the radius is half the length of the diameter)

The problem also states that the radius will increase on thousandth of an inch every 3 minutes. We can find the velocity at which the radius is increasing with this data:

$r'=\frac{1/1000in}{3min}$

which yields:

$r'=\frac{1}{3000}\frac{in}{min}$

with this information we can start solving the problem.

First, the problem wants us to know how fast the volume is increasing, so in order to find that we need to start with the volume formula for a cylinder, which is:

$V=\pi r^{2}h$

where V is the volumen, r is the radius, h is the height and π is a mathematical constant equal approximately to 3.1416.

Now, the height of the cylinder will not change at any time during the reborning, so we can directly substitute the provided height, so we get:

$V=\pi r^{2}(6)$

$V=6 \pi r^{2}$

We can now take the derivative to this formula so we get:

$\frac{dV}{dt}=2(6)\pi r \frac{dr}{dt}$

Which simplifies to:

$\frac{dV}{dt}=12\pi r \frac{dr}{dt}$

We can now substitute the data provided by the problem to get:

$\frac{dV}{dt}=12\pi (1.9) (\frac{1}{3000})$

which yields:

$\frac{dV}{dt}=0.0239\frac{in^{3}}{min}$

3 0

4 years ago

Which situation is most likely to show a constant rate of change

Firdavs [7]

Answer:

B. The amount spent on grapes compared with the weight of the purchase.

Step-by-step explanation:

A: The shoe size of a young girl compared with her age in years. For the first few years of a girl's life, her shoe size is relatively the same. When she goes through a growth spurt, her shoe size increases exponentially. So, that is not a constant rate of change.

B: The amount spent on grapes compared with the weight of the purchase. In most grocery stores, grapes are sold based on their weight, like $2.50 per pound. With each increase in 1 pound, the cost increases by $2.50. That is a constant rate of change.

C: The number of people on a city bus compared with the time of day. This value widely changes throughout the day. For example, during rush hour, there will be many people. But during times at, say, 2 to 3 AM, there will not be many people. So, this is not a constant rate of change.

D: The number of slices in a pizza compared with the time it takes to deliver it. The number of slices in a pizza never changes, so it does not depend on the time it takes to deliver. There is no rate of change.

So, B is your answer.

Hope this helps!

3 0

3 years ago

80 points

Sliva [168]

Answer:

A and c

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers